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Q: Solve x squared plus 2x - 13 equals 2?

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The equation describes a circle with its centre at the origin and radius = âˆš13. Each and every point on that circle is a solution.

5

X +13 equals 22, X equals nine

12 + 5 equals...

To solve for x, we'd have to know what this expression equals.

3 squared plus 2 squared is equal to 13.

It also equals 13 12.

(-3, -5)

this is a pythagorean triple and c2=169 so c=13 25+144=169=132

If: 2a+13 = 5a+1 Then: a = 4

This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.

7+6

13

9 plus 2 squared is equal to 13.

Set up the equation and solve: 13 = 7 + s (next subtract 7 from each side of the equation to solve for s) 6 = s

6+8=14

13=e+2 11=e (subtract 2 from each side)

6x + 8 = 13, 6x = 13 - 8, 6x = 5, x = 5/6

3h+13 = 7 3h = 7-13 3h = -6 h = -2

6x-2=x+135x=15x=3

+6

5

Because the value of C equals 13

9=4a+13 9-13=4a -4=4a -4/4=a -1=a a=-1

13+13=26