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Whether or not the expression can be simplified depends on the value of a. In general, sqrt(2a) = sqrt(2)*sqrt(a).

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โˆ™ 2017-01-01 11:27:49
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What is the quadraic formula?

-b + or - the square root of b squared - 4ac over/divided by 2a


What is the quadratic formula of algebra?

(−b±√b2−4ac)÷2a the square root of b2−4ac entirely.


How do you find the principal square root of a monomial?

Say the monomial is 4a squared. To find the square root to must do each part seperately. So square root of 4 is 2 and the square root of a-squared is |a| because we do not know the sign of a. The answer is 2|a|. If there is anything that cannot be "square rooted" then it would stay under a square root sign and just multiply by 2a as well. The principal root of a number is only its positive root (you can understand that you are looking for the principal root from the sign in front of the radical, which is a positive one)


If RA equals 2a cm What is the area of square YRAM?

One side of the square, RA, is 2a cm. So the area of the square is (2a)2 = 4a2 cm2


What is the Simplify by factoring assume all expressions under radical are nonnegative Square root of 20a2b?

√20a2b = √4a2 * √5b = 2a√5b the answer is 2a times radical 5b.


What are the solutions to the quadratic formula?

The quadratic formula is x=-b (+or-) square root of b2-4ac all over 2a


What is a discriminant and how does help to solve equations?

In the quadratic formula, the discriminant is b2-4ac. If the discriminant is positive, the equation has two real solutions. If it equals zero, the equation has one real solution. If the discriminant is negative, it has two imaginary solutions. This is because you find the square root of the discriminant and add or subtract it from -b and divide the sum or difference by 2a. If the square root is of a positive number, then you get two different solutions, one from adding the discriminant to -b and one from subtracting the discriminant from -b. If the square root is of zero, then it equals zero, and the solution is -b/2a. If the square root is of a negative number, then you have two imaginary solutions because you can't take the square root of a negative number and get a real number. One solution is from subtracting the discriminant from -b and dividing by 2a, and the other is from adding it to -b and dividing by 2a. The parabola on the left has a positive discriminant. The parabola in the middle has a discriminant of zero. The parabola on the right has a negative discriminant.


What is the value of c in the formula square root 2a to the second power plus b to the second power if a is 4 and b to equals 5?

33


What are the terms of a quadratic equation?

x equals negative b plus or minus the square root of b squared minus 4bc over 2a


Give example of a quadratic equations?

X2+5x-6. a=1, b=5, and c=-6 The formula is: -b plus or minus the square root of b squared minus 4ac all over 2a. -b+square root of b2-4ac ---- 2a -5 plus or minus the square root of 5 squared minus 4(1)(-6) -5 plus or minus the square root of 25-4(-6) -5 plus or minus the square root of 25+24 -5 plus or minus the square root of 49 -5 plus or minus 7 Here is where you split into two different answers: Number 1: -5 plus 7= 2 Number 2: -5 minus 7= -12 Your answer is X=2, -12


What is an example of an equation?

Depends what type of equation you want. My favourite is the quadratic equation. (-B plus or minus the square root of B - 4AC) Divided by 2A


How do you write the quadratic formula with parentheses?

x = (-b plus_minus root(b2 - 4ac)) / 2aWhere plus_minus is the "plus or minus" sign, and "root" stands for the square root.


Examples for quadric equation?

The quadric equation is: negative b plus or minus the square root of b squared minus 4ac all over(divided by) 2a


How do you solve a quadratic equation when using a square root?

If you are using square roots, the simplest way of solving: ax2 + bx + c = 0 is x = [-b ± sqrt(b2-4ac)]/(2a)


How do you solve quadratics using the principal square root function?

The first step is to write the quadratic in the form ax^2 + bx + c = 0 where x is the variable and a, b and c are constants. Then the two solutions are [- b - sqrt(b^2 - 4ac)]/(2a) and [- b + sqrt(b^2 - 4ac)]/(2a)


How would you factor 4a2 plus 25?

4a2+ 25 does not factor over the real number field. In the complex numbers , it factors as (2a +5i)(2a - 5i). This is because i2 = -1, so 4a2 + 25 = 4a2 - (- 25) = 4a2 - 25(-1) = 4a2 - 25i2


What is the midpoint and quadratic formula?

midpoint: (x1+x2/2 , y1+y2/2) quadratic: -b plus or minus square root b squared minus 4ac divided by 2a


Where did the quadratic formula come from?

The quadratic formula originated from the concept of completing the square. let's take ax2 + bx + c = 0. To complete the square, solve for x. Subtract c. ax2 + bx = -c. Then divide by a [notice- if there is no a value, then a=1]. x2 + bx/a = -c/a. Add (b/2a)2 to both sides. x2 + bx/a + b2/4a2 = -c/a + b2/4a2 Factor/Reformat. (x + b/2a)2 = (b2-4ac) / 4a2 (x + b/2a)2 = [(b2-4ac) / 2a]2 Square-root both sides. x + b/2a = ± √(b2-4ac) / 2a Subtract b/2a. x = -b/2a ± √(b2-4ac) / 2a Combine terms. x = [-b ± √(b2-4ac)] / 2a


Where did the quadratic equation come from?

The quadratic formula originated from the concept of completing the square. let's take ax2 + bx + c = 0. To complete the square, solve for x. Subtract c. ax2 + bx = -c. Then divide by a [notice- if there is no a value, then a=1]. x2 + bx/a = -c/a. Add (b/2a)2 to both sides. x2 + bx/a + b2/4a2 = -c/a + b2/4a2 Factor/Reformat. (x + b/2a)2 = (b2-4ac) / 4a2 (x + b/2a)2 = [(b2-4ac) / 2a]2 Square-root both sides. x + b/2a = ± √(b2-4ac) / 2a Subtract b/2a. x = -b/2a ± √(b2-4ac) / 2a Combine terms. x = [-b ± √(b2-4ac)] / 2a


What is the length of the diagonal of a square with area 40.5 square inches?

The side is square root of 40.5. ( approximately 6.363961...) The diagonal is 6.363961...times the square root of 2, because of the Pythagorean formula of a^2+b^2=c^2 a^2+a^2=c^2 square has identical sides. 2a^2 =c^2 a * sqr 2=c square root both sides of the equation. a is the side of the square. So, 6.363961... times sqr 2= 9


Which is a factor of 6x2-17x plus 12?

6x² - 17x +12 = Quadratic equation X = (-b +/- (square root of b² - 4ac)) divided by 2a X = (--17 +/- square root of 289-288)) divided by 12 X = 1.5 or 1.333333 recurring


What is the value of x in x squared - 2x - 1 equals 0 please show working outs?

This is a quadratic equation in the form of x2-2x-1 = 0 which will have two solutions and can be solved using the quadratic equation formula: x = -b/2a + and - the square root of (b2-4ac)/2a Whereas in this equation a = 1, b = -2 and c = -1 Solutions: x = 1-the square root of 2 or x = 1+the square root of 2 Remember that (- -2) = 2, (-2)2 = 4 and (-4*1*-1) = 4


Why is the discriminant determines the importances of the number of solutions?

In the quadratic formula, you have -b +- square root of ( b^2 - 4ac) all over 2a. There are three cases:No values:If the discriminant is negative, the square root of b^2 -4ac has no values, because we cannot take the square root of a negative number.One value:If it is zero, than the square root is also zero. This means that there is one solution because +- 0 is always just 0. (-b+-0)/2a only has one value.2 values:if the discriminant is positive then it has a square root. BUT, there is a difference between here and the last step. (-b +- discriminant )/ 2a has 2 values: one for the positive and one for the negative.* * * * *Minor amendment:-b +- square root of ( b^2 - 4ac) all over 2a is the quadratic formula.The discriminant is simply b2 - 4acIf b2 - 4ac > 0 then there are two distinct real roots to the quadratic;If b2 - 4ac = 0 then there is one real roots to the quadratic (or two identical roots);If b2 - 4ac < 0 then there are no real roots to the quadratic.The values of the roots are exactly as described in the earlier answer.


What is the general equation for quadratics?

The general quadratic equation is ax2 + bx + c = 0 The two solutions are: x = [ (negative b) plus or minus the square root of (b2 - 4ac) ] all divided by (2a).


How do you solve a quadratic equation that will not factor?

How you solve an equation that doesn't factor is to plug a quadratic equation's format; ax2+bx+c into the quadratic formula which is x=-b+square root to (b2-4ac)/2a.