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What is the quadraic formula?
-b + or - the square root of b squared - 4ac over/divided by 2a
What is the Simplify by factoring assume all expressions under radical are nonnegative Square root of 20a2b?
√20a2b = √4a2 * √5b = 2a√5b the answer is 2a times radical 5b.
Where did the quadratic formula come from?
The quadratic formula originated from the concept of completing the square. let's take ax2 + bx + c = 0. To complete the square, solve for x. Subtract c. ax2 + bx = -c. Then divide by a [notice- if there is no a value, then a=1]. x2 + bx/a = -c/a. Add (b/2a)2 to both sides. x2 + bx/a + b2/4a2 = -c/a + b2/4a2 Factor/Reformat. (x + b/2a)2 = (b2-4ac) / 4a2 (x + b/2a)2 = [(b2-4ac) / 2a]2 Square-root both sides. x + b/2a = ± √(b2-4ac) / 2a Subtract b/2a. x = -b/2a ± √(b2-4ac) / 2a Combine terms. x = [-b ± √(b2-4ac)] / 2a
Give example of a quadratic equations?
X2+5x-6. a=1, b=5, and c=-6 The formula is: -b plus or minus the square root of b squared minus 4ac all over 2a. -b+square root of b2-4ac ---- 2a -5 plus or minus the square root of 5 squared minus 4(1)(-6) -5 plus or minus the square root of 25-4(-6) -5 plus or minus the square root of 25+24 -5 plus or minus the square root of 49 -5 plus or minus 7 Here is where you split into two different answers: Number 1: -5 plus 7= 2 Number 2: -5 minus 7= -12 Your answer is X=2, -12
How do you calculate the coordinates of the center of the square?
The center of a square is half-way up one side and half-way along the adjacent side, and the sides are the same in a square, so you might say, "1/2A, 1/2A" for the center of a square with one corner at the origin of the axes and having size of A.
