0
The Burns have 2 children. The sum of their ages is 23 and the product is 132. How old are the children?
child 1 = a
child 2 = b
a + b = 23
a x b = 132
a = 23 - b
(23 - b) x b = 132
-b^2 + 23b - 132 = 0
Now it has become a quadratic, you can use the quadratic rule, but i'll bore you no longer
child b = 11 or 12
So The first born child would be 12 years old and the second born would be 11 years old
What else can I help you with?
The burns have 2 children THe sum of their ages is 23 and the product is 132 how old are the children?
X + Y = 23 XY = 132 Y = 23-x xy = x (23-x) = 23x -x2= 132 x2-23x+132 = 0 (X-11)(x-12) = 0 X = 11 Y = 12
What two numbers give a sum of 23 and a product of 132?
11 and 12
What are multiples of 132?
There is an infinite number of multiples of 132. Choose any number and multiply, this will give you a product. Which is the name given to the result of multiplying numbers together. If you choose a number less than 1 then the result will be less than 132 but is also a multiple of it.
What is the a sum of 12 and a product of 11?
The sum of 12 and a product of 11 can be calculated by first finding the product of 12 and 11, which equals 132. Then, adding 12 to this product gives a sum of 144. Mathematically, this can be represented as 12 + (12 x 11) = 12 + 132 = 144.
What two numbers have a difference of 1 and a product of 132?
11, 12 -11, -12
The burns have 2 children THe sum of their ages is 23 and the product is 132 how old are the children?
X + Y = 23 XY = 132 Y = 23-x xy = x (23-x) = 23x -x2= 132 x2-23x+132 = 0 (X-11)(x-12) = 0 X = 11 Y = 12
What are the two conseccutive numbers which product is 132?
11 & 12 are the integers whose product is 132.
What numbers make the product 132?
1+131=132
What is 12x11 equal?
The product is 132
What is the product of 132 and 133?
17,556.
The product of two numbers is 132 what are the two numbers?
They are: 11 times 12 = 132
What is the prom factorization of 132?
As a product of its prime factors: 2*2*3*11 = 132
What 132 prime factor product?
2 x 2 x 3 x 11 = 132
What is the product of two consecutive integers that equals 132?
Let the two consecutive integers be x and x+1. The product of these two integers is x(x+1). Setting this equal to 132 gives us the equation x(x+1) = 132. By expanding the left side of the equation, we get x^2 + x = 132. Rearranging terms, we have x^2 + x - 132 = 0. This is a quadratic equation that can be factored as (x+12)(x-11) = 0. Therefore, the two consecutive integers are 11 and 12, and their product is 132.
Express 169 as a product of prime factors?
169 = 132
What is the LCM of 5 3 11 and 12?
The least common multiple of 3, 11 and 12 is 132.
What two numbers give a sum of 23 and a product of 132?
11 and 12
