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80-5= 75

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Q: The age of an octogenarian in years divided by number of diagonals in a pentagon is?
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Related questions

What is the number of diagonals in a pentagon?

5


Number of diagonals in a pentagon?

0.5*(25-15) = 5 diagonals


How many diagonals in pentagon have?

It has 5 diagonals.Formula: number of distinct diagonals = n(n-3)/2where n is the number of sides (or vertices)number of diagonals in pentagon:= 5(5-3)/2= 5(2)/2= 10/2= 5Answer: There are 5 diagonals in pentagon.


Total number of diagonals in pentagon?

14


How do you find the diagonals in a pentagon?

Use the formula: 0.5*(n2-3n) whereas 'n' is the number of sides of the polygon So: 0.5*(25-15) = 5 diagonals


What is the largest number of diagonals that can be drawn inside a polygon with n sides?

Formula: number of diagonals = 1/2 * n(n-3) where n is the number of sides or vertices Example: to get the number of diagonals in a pentagon pentagon has 5 sides or vertices; thus, n = 5 no. of diagonals: = 1/2 * n(n-3) = 1/2 * 5(5-3) = 1/2 * 5(2) = 1/2 * 10 = 10/2 = 5


How many diagonals do hexagons have?

The number of diagonals in an n-sided polygon is given by nC2 - n (where n is the number of sides of the polygon) or in the expanded form: factorial (n) _______________________ {factorial (2) * factorial (n-2)} substituting (n = 6) for a hexagon we get the number of diagonals as 9. Similarly, substituting (n=5) for a pentagon we get the number of diagonals as 5.


How do you find the number of diagonals in a shape?

you subtract 3 from the number of sides then multiply that by the number of sides divided by 2


In pentagon the no of diagonals is 5 how?

Trace from each corner to each other corner that it is not directly connected to. count the number of lines within the shape.


Does a pentagon have 2 diaginols?

A pentagon has 5 diagonals.From any one corner, you can draw two diagonals. There are five corners, so that would mean a total of 5 times you could draw 2 diagonals, equalling 10, except that you'd be counting each diagonal twice - once from each of its ends. So, you divide the total number of ten in half, and get 5.The formula for number of diagonals of any polygon is n*(n-3)/2, where n is the number of sides.


What polygon has the same number of diagonals as it has sides?

In short: The Pentagon In Long: The formula for the number of diagonals is (x*(x-3))/2 So if you make that equal to x you get 5. (x(x-3))/2=x (x^2-3x)/2=x x^2-3x=2x x^2-5x=0 x=0 or x-5=0 x=0 or x=5 x=5 Because there is no polygon with 0 sides and the pentagon is defined as a polygon with 5 sides, the pentagon is the only regular polygon with the same amount of diagonals as it has sides.


What is the connectionbetween the number of sides of the polygon and the number of triangles into which it may be divided by drawing diagonals from one vertex?

Number of sides minus 2 equals the number of triangles within the polygon.