Formula:
number of diagonals = 1/2 * n(n-3)
where n is the number of sides or vertices
Example: to get the number of diagonals in a pentagon
pentagon has 5 sides or vertices; thus, n = 5
no. of diagonals:
= 1/2 * n(n-3)
= 1/2 * 5(5-3)
= 1/2 * 5(2)
= 1/2 * 10
= 10/2
= 5
The five sided Polygon has 5 diagonals
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
A polygon with 14 diagonals will have 7 sides
14 diagonals
The formula for the number of diagonals is: 0.5*(n^2-3n) whereas 'n' is the number of sides of the polygon
The five sided Polygon has 5 diagonals
A 7 sided polygon has 14 diagonals
It is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
Number of diagonals = 1/2*(n2-3n) where n = the number of sides of the polygon.
A polygon with 14 diagonals will have 7 sides
The equation is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
It has 20 diagonals
14 diagonals
You can find the number of diagonals in a polygon using the formula n(n-3)/2, where n is the number of sides. Therefore an 11 sided polygon has 44 diagonals.
It is: 0.5*(n2-3n) = diagonals whereas 'n' is the number of sides of the polygon
38 diagonals