To have an altitude of 8 cm it could have a base of 12 cm and two equal sides of 10 cm which would satisfy Pythagoras' theorem because an isosceles triangle is in fact two right angle triangles joined together.
Area of a triangle = 1/2*base*height
Area = 1/2*12*8 = 48 square cm
An isosceles triangle has 3 sides and 2 of its sides are of equal length which can be constructed by using a straight edge and a compass.
The Isosceles triangle only has one possible line of symmetry; and that is through the vortex, AKA: The middle, in a vertical line.
Yes, every isosceles triangle has at least one line of symmetry, usually drawn down the middle from the top point, down in the middle of the triangle's base.
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base?
There is not enough information for an unambiguous answer. If the missing side is the hypotenuse, then the altitude is 4.910 units. If the missing sides is one of the legs of the triangle, the altitude is 4.907 units.
Not necessarily. That only happens in isosceles and equilateral triangles.
An isosceles triangle has 3 sides and 2 of its sides are of equal length which can be constructed by using a straight edge and a compass.
isosceles triangle
The Isosceles triangle only has one possible line of symmetry; and that is through the vortex, AKA: The middle, in a vertical line.
Yes, every isosceles triangle has at least one line of symmetry, usually drawn down the middle from the top point, down in the middle of the triangle's base.
In the diagram, ABC is an isoscels triangle with the congruent sides and , and is the median drawn to the base . We know that ∠A ≅ ∠C, because the base angles of an isosceles triangle are congruent; we also know that ≅ , by definition of an isosceles triangle. A median of a triangle is a line segment drawn from a vertex to the midpoint of the opposite side. That means ≅ . This proves that ΔABD ≅ ΔCBD. Since corresponding parts of congruent triangles are congruent, that means ∠ABD≅ ∠CBD. Since the median is the common side of these adjacent angles, in fact bisects the vertex angle of the isosceles triangle.
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base?
An altitude is a perpendicular drawn from a point to the opposite segment while a median is a segment drawn from a point to the opposite side such that it bisects the side.Altitudes and their concurrenceMedians and their concurrence
Sure. If one of the base angles is more than 90 degrees, then the altitude (height) is outside the triangle. Yes. This only occurs with an obtuse triangle. Because an altitude is a line drawn from a vertex to the opposite side and is perpendicular with that opposite side, it can only occur if it is outside the triangle. Look at the triangle in related links. If you look at the vertex on the top, the only way to draw the altitude would be to draw outside the triangle.
If it's a right angle triangle then use Pythagoras' theorem to find the 3rd side
If a remains the right triangle, No
There is not enough information for an unambiguous answer. If the missing side is the hypotenuse, then the altitude is 4.910 units. If the missing sides is one of the legs of the triangle, the altitude is 4.907 units.