A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base?
The formula for the area (R) of a rectangle is R = length x width = 12 x 8 = 96 sq in.The formula for the area (T) of a triangle is T = 1/2 base x altitude (a)(or vertical height) Then 96 = 1/2 x 32 x a : 96 = 16a : therefore a = 6 inches.Answer : The altitude of the triangle = 6 inches
6 inches
Area of the rectangle = (Length x Width) = (12 x 8) = 96Area of the triangle = 1/2 (Base x Altitude) = 1/2 (32 x Alt) = also 96 1/2 (32 x Alt) = 96 32 x Alt = 192 Alt = 192/32 = 6 inches
Use Pythagoras' theorem: 92-4.52 = 60.75 and the square root of this is the altitude which is 7.794 inches to 3 d.p.
a rectangle as a longer side because there's 48 inches for a rectangle but there's only 45 inches for a triangle. a rectangle as a longer side because there's 48 inches for a rectangle but there's only 45 inches for a triangle.
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base? WRONG WRONG WRONG NO NO NO ::"::":""::":"""::"":":""::::::::::::: ::"::": ::":: :: ::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::"
6
6
The rectangle has an area of 12 x 8 = 96 square inches. The triangle has an area of (1/2 * 32 * x). So, 16x = 96, therefore x = 6. The height of the triangle is 6 inches.
The formula for the area (R) of a rectangle is R = length x width = 12 x 8 = 96 sq in.The formula for the area (T) of a triangle is T = 1/2 base x altitude (a)(or vertical height) Then 96 = 1/2 x 32 x a : 96 = 16a : therefore a = 6 inches.Answer : The altitude of the triangle = 6 inches
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The altitude will be 6 inches in length. The area of the rectangle is length (l) times width (w) or l x w = 12 x 8 = 96 The area of a triangle is 1/2 the base (b) times the height (h), or altitude, and, because the area of the triangle is equal to the area of the rectangle, both will have an area of 96. For the triangle, 1/2 b x h = 1/2 x 32 x h = 96, and 16 x h = 96, and h = 6
6 inches
Area of the rectangle = (Length x Width) = (12 x 8) = 96Area of the triangle = 1/2 (Base x Altitude) = 1/2 (32 x Alt) = also 96 1/2 (32 x Alt) = 96 32 x Alt = 192 Alt = 192/32 = 6 inches
Area Rectangle = 12 * 8 = 96 sq. in.Area Triangle = 1/2 base * height -> 96 = 16 * height -> 96 / 16 = height = 6 in.
To find the diagonal length of a rectangle use Pythagoras' theorem for a right angle triangle.