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A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches altitude drwn to ba?
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base? WRONG WRONG WRONG NO NO NO ::"::":""::":"""::"":":""::::::::::::: ::"::": ::":: :: ::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::"
Line drawn between 2 vertices which are not next to each other?
To find the length of a line drawn between 2 vertices which are not next to each other, first draw a right triangle such that the line is the hypotenuse and the other two lines are drawn parallel to the x-axis and y-axis. Since the length of the other two lines are known, you can then calculate the hypotenuse to find the length of the line between the two vertices.
A rectangle and triangle have equal areas - the rectangle's length is 12 inches and its width is 8 inches so if the base of the triangle is 32 inches what is the length in inches of the altitude drawn?
The rectangle has an area of 12 x 8 = 96 square inches. The triangle has an area of (1/2 * 32 * x). So, 16x = 96, therefore x = 6. The height of the triangle is 6 inches.
Is an altitude ever outside a triangle?
Sure. If one of the base angles is more than 90 degrees, then the altitude (height) is outside the triangle. Yes. This only occurs with an obtuse triangle. Because an altitude is a line drawn from a vertex to the opposite side and is perpendicular with that opposite side, it can only occur if it is outside the triangle. Look at the triangle in related links. If you look at the vertex on the top, the only way to draw the altitude would be to draw outside the triangle.
A rectangle and triangle have equal areas. The rectangle is 12 inches long and 8 inches wide. If the base of the triangle is 32 inches what is the length in inches of the altitude drawn to the base?
The altitude will be 6 inches in length. The area of the rectangle is length (l) times width (w) or l x w = 12 x 8 = 96 The area of a triangle is 1/2 the base (b) times the height (h), or altitude, and, because the area of the triangle is equal to the area of the rectangle, both will have an area of 96. For the triangle, 1/2 b x h = 1/2 x 32 x h = 96, and 16 x h = 96, and h = 6
What is the length of an altitude drawn to a hypotenuse if the only given sides are 5 and 26?
There is not enough information for an unambiguous answer. If the missing side is the hypotenuse, then the altitude is 4.910 units. If the missing sides is one of the legs of the triangle, the altitude is 4.907 units.
What is the length of a perpendicular line drawn from one vertex to the opposite side?
The length of a perpendicular line drawn from one vertex to the opposite side of a triangle is known as the altitude. It varies depending on the type of triangle and the position of the vertex from which the altitude is drawn. The altitude can be calculated using the area of the triangle and the length of the base to which it is perpendicular. In general, the altitude is crucial for determining the triangle's area and properties.
A rectangle and triangle have equal areas the length of the rectangle is 12 in and its width is 8 in if the base of the triangle is 32 in what is the length in inches of the altitude drawn to the base?
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base?
If in a right triangle a is perpendicular and b is base and h is hypotenuse and an altitude p is drawn on p then is a plus b equals h plus p?
If a remains the right triangle, No
When a circle is drawn through each vertex of a right triangle the triangles hypotenuse will be equal to what?
The length of the circle's diameter
What is the altitude of an isosceles triangle that has the same segment called?
In an isosceles triangle, the altitude drawn from the vertex angle to the base bisects the base and is perpendicular to it. This segment is often referred to as the "height" of the triangle. The altitude can be calculated using the formula involving the base and the length of the equal sides, but its specific length depends on those dimensions.
The length of the rectangle is 12 inches and its width is 8 inches if the base of a triangle is 32 inches what is the length in inches of the altitude drawn to the base?
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A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches altitude drwn to ba?
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base? WRONG WRONG WRONG NO NO NO ::"::":""::":"""::"":":""::::::::::::: ::"::": ::":: :: ::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::"
When a circle is drawn through each vertex of a right triangle the triangle's hypotenuse will be equal to?
Its diameter.
Line drawn between 2 vertices which are not next to each other?
To find the length of a line drawn between 2 vertices which are not next to each other, first draw a right triangle such that the line is the hypotenuse and the other two lines are drawn parallel to the x-axis and y-axis. Since the length of the other two lines are known, you can then calculate the hypotenuse to find the length of the line between the two vertices.
If abce is an isosceles trapezoid and acde is a rectangle what is the length of ae when ab equals 10 and ec equals 20?
Draw the isosceles trapezoid ABCE, where the length of the bases AB (on the top) and EC are respectively 10 and 20. From A and B draw the perpendiculars to the base EC of the trapezoid, and label the point of intersections with F and G). The rectangle ABGF is formed, where the length of FG is 10 (since the two opposite sides of a rectangle are congruent). Then the lengths of EF and GC are 5 (since the trapezoid is isosceles). Draw the diagonal AC. From C and E draw the parallel lines respectively to AE and AC, and label the intersection point with D. So the rectangle ACDE is formed. Thus, the triangle EAC is a right triangle, where the angle A is 90 degrees (as the angle of a rectangle), and AF is the altitude drawn at the hypotenuse EC. We have a theorem that states: "If an altitude is drawn to the hypotenuse of a right triangle, then each leg is the geometric mean between the hypotenuse and its touching segment on the hypotenuse". So we have, EC/AE = AE/EF, which yields AE2 = EC*EF, and so AE = √(20*5) = 10. or using the same diagram, Since the diagonals of a rectangle bisect each other (let's say they bisect at H), then AH is the median of the right triangle EAC, drawn to the hypotenuse EC, so its length is the half of the hypotenuse. So the length of AH is 10. Since the trapezoid is isosceles, then the diagonal BE also will form a right triangle EBC, where the median BH also it is 10. So the triangle ABH is equilateral, where angle A is 60 degrees, and it is congruent with angle H of the triangle AHE, as two alternate interior angles. Thus, the isosceles triangle AHE is also equilateral, where AE = 10.
How do you draw an isoscles right angled triangle?
An isosceles triangle is usually drawn with the two sides of equal length as the legs and the third side as the base. For a right angled isosceles triangle then the hypotenuse is drawn as the base with the two sides of equal length as the legs joining together at a right angle. Draw a circle. Draw a horizontal diameter with a second diameter perpendicular to the first. The hypotenuse is the horizontal diameter. Draw lines from the ends of this diameter to the point where one end of the second diameter meets the circumference. These are the two equal legs of the isosceles triangle. These legs meet at an angle of 90° .
