Q: The average of four numbers is 5 What is their sum?

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Sum of 5 numbers with an average of 10 = 50

Average of five numbers is 82 so their sum is 82*5 = 410. Average of four of them is 80, so their sum is 80*4 = 320. So the fifth number is 410 - 320 = 90.

the sum of all numbers is 6*4=24 sum of two = 2*2=4 average of other four=24-4/4=5

Their sum divided by 5.

If the average of 5 numbers is 86, then their sum is 430.If the average of 6 numbers is 84, then their sum is 504.The sum grew by (504 - 430) = 74, so that was the 6th number.

The average of a group of numbers is equal to the sum of the numbers divided by the number of numbers. If you want to find the sum of the five numbers, just multiply 790.6 by 5 to get the sum, which is 3953

If the sum of 5 = 28 then the average is 28 / 5 = 5.6 If the sum of the squares = 226 then the average is 226 / 5 = 45.2 From this information, and by a process of elimination, the numbers might be 1, 2, 6, 8 and 11.

250

12.5 To find the average of a group of numbers, add all the numbers together and divide the sum by the number of numbers that were added together. Example: 5 + 10 + 15 + 20 = 50. Divide the sum (50) by 4 (you added four numbers together to get the sum): 50 divided by 4 = 12.5

The average of a set of numbers is the sum of all the numbers, divided the amount of numbers in the sequence. For example, the average of 12, 14, 13, 15, and 20, would be the sum of the numbers, 74, divided by the amount of numbers in the sequence, 5. So the average is 74/5, which is 14.8.

5

1)start 2)input 5 numbers m,a,i,r,a 3)average=sum/5 4)printsum 5)stop

Assuming mean average: average = sum/number_of_items → 10 = sum/2 → sum = 10 x 2 = 20 So any two numbers with a sum of 10 have a mean average of 10, eg {5, 15}, {1, 19}, {0, 20}, {-5, 25}, etc. With the median average, for two numbers it is exactly the same as the mean average, so any pair of numbers that sum to 20 will do. With the mode average, only the case of the pair of numbers {10, 10} will suffice.

The average (arithmetic mean) is the sum of the values divided by the number of values.Example : 5, 9, 10Their sum is 5+9+10 = 24 and there are 3 numbersThe average is 24/3 = 8

23*5 = 115 So pick any four numbers: integers, fractions, irrational numbers, whatever. Add them together to give a sum S. Let the 5th number be 115 - S Then: sum of all five numbers = (sum of the first four numbers) + (the fifth number) = S + (115 - S) = 115 And the count of numbers = 5 So mean = Sum/Count = 115/5 = 23

17 is the only prime number that is the sum of four consecutive prime numbers. 2 + 3 + 5 + 7 = 17

average = 37average of numbers 25 30 45 35 50 = sum/5= 185/5= 37

Add the numbers together (sum) and divide by two (average). SUM: 2 + 8 = 10 AVG: 10 / 2 = 5

1, 2, 3, and 5

2, 3, 5, and 7

The mean of a series of numbers is the average - calculated by added all the numbers in the series and dividing the sum by the number of numbers in the series. Given the set of numbers {1,2,3,4,5}, the sum of these numbers [1+2+3+4+5=15] divided by 5 {n=5}, gives a mean or average of 3.

import java.util.Scanner;public class average {static int i=0;static double sum = 0;static double average = 0;public static double calcSum(double sum){double count;Scanner input = new Scanner(System.in);while(i < 5){count = input.nextDouble();sum = sum + count;i++;}return sum;}public static double calcAverage(double average){double sum = calcSum(sum);average = calcSum(sum) / 5;return average;}public static void main(String[] args) {System.out.println("Please enter 5 numbers.");System.out.println("Sum is: "+calcSum(sum));System.out.println("Average is: "+calcAverage(average));}}

Any set of four numbers that totals 20 has an average of 5.3, 4, 6, 7

average of first five prime numbers = 5.6 first five prime numbers = 2, 3, 5, 7, 11average = sum of first prime numbers/5= (2 + 3 + 5 + 7 + 11)/5= 28/5= 5.6

4 + 5 = 9 4 and 5 are two numbers with the sum of 9 and have a difference of 5

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