250
Sum of 5 numbers with an average of 10 = 50
The average of five numbers whose sum is 200 will always be 40, no matter which numbers you choose. When finding an average, you add up the numbers (find the sum of the set), then divide by the number of terms. In this case, the sum will always be 200, and there will always be five terms. This will always result in an average of 40. Ex/ 1 + 2 + 3 + 4 + 190 = 200 200 / 5 = 40 40 + 40 + 80 + 24 + 16 = 200 200 / 5 = 40
There are no 5 odd numbers whose sum is 50. (The sum of 5 odd numbers is an odd number whereas 50 is an even number.)
To find the fifth number, you can use the formula for finding the average of a set of numbers. The sum of the 5 numbers is 82 * 5 = 410. The sum of the 4 known numbers is 80 * 4 = 320. Therefore, the fifth number can be found by subtracting the sum of the 4 known numbers from the sum of all 5 numbers: 410 - 320 = 90. So, the fifth number is 90.
10 + 5 = 15 10 x 5 = 50
Sum of 5 numbers with an average of 10 = 50
The average of five numbers whose sum is 200 will always be 40, no matter which numbers you choose. When finding an average, you add up the numbers (find the sum of the set), then divide by the number of terms. In this case, the sum will always be 200, and there will always be five terms. This will always result in an average of 40. Ex/ 1 + 2 + 3 + 4 + 190 = 200 200 / 5 = 40 40 + 40 + 80 + 24 + 16 = 200 200 / 5 = 40
average = 37average of numbers 25 30 45 35 50 = sum/5= 185/5= 37
12.5 To find the average of a group of numbers, add all the numbers together and divide the sum by the number of numbers that were added together. Example: 5 + 10 + 15 + 20 = 50. Divide the sum (50) by 4 (you added four numbers together to get the sum): 50 divided by 4 = 12.5
There are no 5 odd numbers whose sum is 50. (The sum of 5 odd numbers is an odd number whereas 50 is an even number.)
Their sum divided by 5.
-5, 10
If the average of 5 numbers is 86, then their sum is 430.If the average of 6 numbers is 84, then their sum is 504.The sum grew by (504 - 430) = 74, so that was the 6th number.
The average of a group of numbers is equal to the sum of the numbers divided by the number of numbers. If you want to find the sum of the five numbers, just multiply 790.6 by 5 to get the sum, which is 3953
If the sum of 5 = 28 then the average is 28 / 5 = 5.6 If the sum of the squares = 226 then the average is 226 / 5 = 45.2 From this information, and by a process of elimination, the numbers might be 1, 2, 6, 8 and 11.
To find the fifth number, you can use the formula for finding the average of a set of numbers. The sum of the 5 numbers is 82 * 5 = 410. The sum of the 4 known numbers is 80 * 4 = 320. Therefore, the fifth number can be found by subtracting the sum of the 4 known numbers from the sum of all 5 numbers: 410 - 320 = 90. So, the fifth number is 90.
To write pseudocode that accepts five numbers and displays their sum and average, you can follow these steps: Initialize a variable sum to 0. Loop five times to accept input for each number, adding each to sum. After the loop, calculate the average by dividing sum by 5. Display both the sum and the average. Here’s a simple representation: BEGIN sum = 0 FOR i FROM 1 TO 5 DO INPUT number sum = sum + number END FOR average = sum / 5 OUTPUT "Sum: ", sum OUTPUT "Average: ", average END