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The half-life of fluorine-20 is 114 seconds After 14 seconds how much of the original amount of fluorine-20 will remain?
Wiki User
∙ 14y ago
THE QUESTION IS INVALID. THE HALF-LIFE OF FLUORINE-20 is 11.07 SECONDS.
There will be about 0.92 of of an isotope with a half-life of 114 seconds remaining after 14 seconds.
The equation for half-life decay is AT = A0 2(-T/H) where T is time and H is half-life.
2(-14/114) is equal to about 0.92.
In the case of fluorine-20, 2(-14/11.07) is about 0.42.
Wiki User
∙ 14y ago
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