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The half life of fluorine-20 is 11.4 seconds After seconds 1'4 of the original amount of fluorine-20 will remain?
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∙ 14y ago
22.8 seconds
Wiki User
∙ 14y ago
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The remainder is 2-p or 0.5p of the original amount.
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The half-life of fluorine-20 is 11.4 seconds After seconds 1 4 of the original amount of fluorine-20 will remain?
25
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After 5.4 days
The half-life of gold198 is 27 days After days 14 of the original amount of gold198 will remain?
5.4
What fraction of a radioactive nuclei remain after p half lives?
The remainder is 2-p or 0.5p of the original amount.
The half life of cobalt 60 is 5.3 years After years 14 of the original amount of cobalt 60 will remain?
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The half-life of cobalt-60 is 5.3 years After years 1 4 of the original amount of cobalt-60 will remain?
After twice the half-life, 1/4 of the original amount remains. After 3 times the half-life, 1/8 of the original amount remains. Etc.
The half-life of fluorine-20 is 114 seconds After 14 seconds how much of the original amount of fluorine-20 will remain?
THE QUESTION IS INVALID. THE HALF-LIFE OF FLUORINE-20 is 11.07 SECONDS. There will be about 0.92 of of an isotope with a half-life of 114 seconds remaining after 14 seconds. The equation for half-life decay is AT = A0 2(-T/H) where T is time and H is half-life. 2(-14/114) is equal to about 0.92. In the case of fluorine-20, 2(-14/11.07) is about 0.42.
How many grams are left after sixty seconds of rhodium one hundred six if the half life is thirty seconds?
1/4 of the amount that was originally there will remain. Note that the rest doesn't simply evaporate, it will decay into something else.
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