W = x
L = x + 2
A = LW
A = (x + 2)(x)
A = x2 + 2x
length is 12 width 1
For a given perimeter, its a square.
Area = length x width Length = area/width
168 square feet.
If Length * Width = Area, then Area ÷ width = Length
The area of a rectangular garden is length * width. You have 200 = Length * 20, and so Length = 10 metres. Conventionally, for a rectangle, the length is the longer of the two dimensions, though for a garden, it is often the distance from the back of the house to the end of the garden that is referred to as the length - even if it is the shorter dimension.
x^2 + 2x ft
Length of garden = 2 times its width plus 5 feet Let 2x+5 = length and let x = width Area of sidewalk = 6x = 213 square feet x = 35.5 feet which is the width of the garden 2*35.5+5 = 76 feet which is the length of the garden
Area of a rectangle is length times width, therefore if the length is two feet longer than the width then the length is 9 and the width is 7, when they are multiplied you get 63
if the diameter of the gardenis 66 metes and the measure of a is 118.8 what will the area of the fountain be?(use 3.14for.)
Length of rectangle garden is 5 m greater than the width. the area is 84 m2. find the dimensions of the garden.
length is 12 width 1
Area=Length * Width. if length =4 and width =5...area is 20. if doubled....(4*2)*(5*2)=A*4. When length and width double, area is multiplied by 4.
Let the length be 2x and the width be x: length*width = area 2x*x = 50 2x2 = 50 x2 = 25 x = 5 feet
A = area, L = length, W = width A = LW L = 2W A = (2W)W = 2W2 2W2 = 50 W = 5 ft
For a given perimeter, its a square.
the length of a rectangular garden is 12 meters and the width is 7 meters. What is the area