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Designate the width in feet by w. By the statement of the problem, the length is then w+2. The area of any rectangle is the product of the length and the width, or w(w+2) = 8. Multiplying out and collecting all terms on one side yields w2 + 2w - 8 = 0. The polynomial can be factored into (w + 4)(w - 2) = 0, which is true when w = 2 or -4. The length of a physical rectangle can not be negative; therefore, the width is 2 feet and the length 4 feet.

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Q: The length of a rectangle is 2 feet longer than the with what is the dimensions if the area is 8ft?
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