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The dimensions are 16 units by 8 units of mearsurement

Q: There area of the rectangle is 128. If the width is twice the length what is the length?

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From the statement of the problem, if w is the width, the area is 2w2 , the product of the width and the length, which is stated to be twice the width. Since 2w2 must be less than 50, w2 < 25, and the width must be less than 5 meters.

length times width

area of a rectangle = length * width. Rearranging, we have width = area / length. Therefore, the width of the rectangle = 31.2 [m2] / 6 [m] = 5.2 [m] ========================

Length = 4, Width = 2

Width * Length = Area so..... Width = Area / Length

Related questions

The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.

2x4

L=16 in W=8 in

156 It is impossible to calculate the area of a rectangle from its perimeter if no other dimension is known. The area of a rectangle is the product of its length and width, and the perimeter is twice the sum of its length and width.

Area is length times width, perimeter is twice the sum of length and breadth.

The width is 6 cm and the length is 12 cm.

98 square feet

It is: 10 times 5 = 50 square in

For a rectangle or square, Area = Length * Width So Length = Area / Width.

A = lw Area of a rectangle = length times width

8 ft.

50 cm2