Presumably the area is 16 ft 2ins which is 16.1666666 ft
If so then let the length be (x+2) and the width be x:
length*width = area
(x+2)*x = 16.1666666
x2+2x-16.1666666 = 0
Solving the above quadratic equation gives a positive value for x as 3.143267624
Therefore: length = 5.143267624 ft and width = 3.143267624 ft
Check: 5.14367624*3.14326724 = 16.1666666 square feet
Let x be the width of the rectangle. Then the length is 3x. The area of the rectangle is 3x * x = 3x^2, which also has to be 48. Solving for x, we get that the width is 4, and the length is 12.
For a rectangle or square, Area = Length * Width So Length = Area / Width.
width is 5 feet
length times width equals the area of a rectangle. length times width equals the area of a rectangle. area
Area of rectangle divided by its length = width of rectangle
Area of a rectangle is length times width, therefore if the length is two feet longer than the width then the length is 9 and the width is 7, when they are multiplied you get 63
Area of a rectangle: length times width Width=11 Length= 11x3= 33 11x33= 363 square feet
The length is 7 feet and the width is 5 feet
The width is 6 feet. The length is 8 feet.
Let x be the width of the rectangle. Then the length is 3x. The area of the rectangle is 3x * x = 3x^2, which also has to be 48. Solving for x, we get that the width is 4, and the length is 12.
For a rectangle or square, Area = Length * Width So Length = Area / Width.
A = lw Area of a rectangle = length times width
width is 5 feet
length times width
For a rectangle, area equals length times width. To find the length given the width and area, divide the area by the width.
It is the area of the rectangle which is length times width
21cm3