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Let L be the length and W be the width of the rectangle.

Given:

2(W+L) = 18 -- (1)

L=2W-3 -------- (2)

Solution:

From (2), 2W = L+3 --- (3)

substitute (3) into (2). We get (L+3)+2L = 18.

3L + 3 = 18

L = 5.

Substitute into (2)

W = 4.

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Q: The length of a rectangle is 3 inches less than twice the width if the perimeter of the rectangle is 18 inches?
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