If you increase the rectangle's length by a value, its perimeter increases by twice that value. If you increase the rectangle's width by a value, its perimeter increases by twice that value. (A rectangle is defined by its length and width, and opposite sides of a rectangle are the same length. The lines always meet at their endpoints at 90° angles.)
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
The dimensions of the rectangle are 21 units by 9 units
The perimeter of a rectangle is 42. Meters. The length of the rectangle is threemeter less than twice the width.Mar
A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.
4cm by 13cm
15m wide and 31m long
Area is length times width, perimeter is twice the sum of length and breadth.
The perimeter of any rectangle is twice the sum of the length and the width of the rectangle; in the present instance, 2(n + 2n) = 6n.
Perimeter of a rectangle = twice (length + width), in this case 22 m.
Length = (Perimeter - twice width) / 2
The dimensions work out as length 15 units and width 8 units Check: 2*(15+8) = 46 units which is its perimeter
156 It is impossible to calculate the area of a rectangle from its perimeter if no other dimension is known. The area of a rectangle is the product of its length and width, and the perimeter is twice the sum of its length and width.
If the width is 9' and the length is twice that, the length is 18'; the perimeter is twice the length plus twice the width, which is 36' + 18' = 54 feet.
The perimeter of a rectangle is twice the sum of the width and length: perimeter = 2 x (4.6in + 12.1 in) = 33.4 in
The length is 14 cm
The perimeter of a rectangle is twice the length plus twice the width so half the perimeter is the length plus the width. If the perimeter is 12 m, then the length plus the width must equal 6. The dimensions could therefore be 1 m x 5 m, 2 m x 4 m, 3 m x 3 m (although this would be a square), 4 m x 2 m or 5 m x 1 m.
16 and 12
98 square feet
The length is 20 units and the width is 10 units
Designate the width by w. Then, from the problem statement, the length = 6 + 2w. The perimeter is twice the width plus twice the length, or: 2w + 2(2w + 6) = 36; or 2w + 4w + 12 = 36; or 6w = 24 or w = 4 meters; the length is 14 meters.