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6x2+19x+10 = (2x+5)(3x+2) Length = 2x+5 Width = 3x+2
Add them together and then double it.x+6+2x=3x+6P=6x+12
Length = 2x+2Width = x + 4Perimeter = 2 (Length + Width) = 2 [(2x + 2) + (x +4)] = 2 (3x + 6) = 6x + 12Answer is 6x + 12
Let the length be 2x and the width be x: 2(2x+x) = 66 4x+2x = 66 6x = 66 x = 11 feet length = 22 feet and width = 11 feet
Width = 2x - 5Length = 4Area = (length) x (width) = 8x - 20
6x2+19x+10 = (2x+5)(3x+2) Length = 2x+5 Width = 3x+2
Let the width = X. The length is twice the width plus 5. So the length must be 2X + 5. Area = 63 ft squared = X multiplied by 2X + 5 = 2X squared + 25. 2X squared = 63 - 25 = 38 2X = square root of 38. Therefore the width is the square root of 38 divided by 2 and the length is the square root of 38 plus 5.
Add them together and then double it.x+6+2x=3x+6P=6x+12
If the rectangle has a width of x inches, and a length of x + 16 inches, then its perimeter equals to 2x + 2x + 32 or 4x + 32. If x = 14, then x + 16 = 30. So the perimeter of rectangle becomes 2(14) + 2(30) = 28 + 60 = 88 inches.
Length = 2x+2Width = x + 4Perimeter = 2 (Length + Width) = 2 [(2x + 2) + (x +4)] = 2 (3x + 6) = 6x + 12Answer is 6x + 12
a rectangle has a length of 2x-5 units and a width of x-3 units. what is the area, in square units, of the rectangle?
First find the dimensions of the rectangle. Let its length be 2x and its width be x: 2(2x+x) = 60 4x+2x = 60 6x = 60 x = 10 Therefore: length = 20cm and the width = 10cm Area = length*width Area = 200cm2
Let the length be 2x and the width be x: 2(2x+x) = 66 4x+2x = 66 6x = 66 x = 11 feet length = 22 feet and width = 11 feet
2(2x) +2x = 100
2 (x + 2x) = 42 x + 2x = 21 3x = 21 Therefore, x = 7 The width of the rectangle is 7 inches. The length of the rectangle is 14 inches.
2x+4 + 2x +4 + 3x +6 + 3x +6 = 100 10x + 20 = 10010x = 80x= 8Length = 2(8) + 4 = 20Width = 3(8) + 6 = 30
Width = 2x - 5Length = 4Area = (length) x (width) = 8x - 20