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No. The log of a quotient is the log of a denominator subtracted from the log of the numerator.

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Q: The log of a quotient is the log of a numerator divided by the log of the denominator?
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The log of a quotient is the log of the numerator divided by the log of the denominator?

Not quite. The log(x/y) = log(x) - log(y) In words, this reads "The log of a quotient is the difference of the log of the numerator and the log of the denominator."


The log of a quotient is the log of a numerator divided by the log of the denominator true or false?

False When logs are taken, division becomes subtraction, so the log of a quotient is the log of the numerator minus the log of the denominator.


The log of the quotient is the log of the numerator plus the log of the denominator?

No. Insert the word "minus" in place of the word "plus", and you'll have a true statement.


The log of a quotient is the log of the numerator minus the log of the denominator?

True. For example: 4 X 104/2 X 108 = 2 X 10-4


An equation that has variables in both the numerator and denominator?

It has no specific name. For example f(x) = sin(x)/log(x) where x not equal to 1


What is 4 divided by 84 in log division?

4 divided by 84 in log div = 0.047619047619047616


What is -log equivalent to?

The negative log of a number is the log of the number's reciprocal ('1' divided by the number).


Derivative of log?

The derivative of a log is as follows: 1 divided by xlnb Where x is the number beside the log Where b is the base of the log and ln is just the natural log.


What is log 11 divided by log 20?

0.55


How do you solve nernst equation?

VK= RT/ZF * log [I+]out/[I+]inAccording to this equation, the equilibrium potential for potassium (VK) is equal to the product of the gas constant (R) and the temperature in degrees Kelvin (T) divided by the product of the valence of potassium (Z) and the Faraday constant (F) multiplied by the natural log of the quotient derived from the external and internal concentrations of potassium. Thus,


How does decibels work?

To calculate the number of decibels that power-level-'A' is greater than power-level-'B',-- Divide 'A' by 'B'-- Take the 'log' of the quotient-- Multiply the 'log' by 10 .If the result is negative, then 'A' is that many decibels lower than 'B'.


How would you rearrange this formula to find x. 1.075 to the power of x equals 3445.51 divided by 2400?

log y (3445.51/2400) / log 1.075 = x