No. The log of a quotient is the log of a denominator subtracted from the log of the numerator.
The browser which is used for posting questions is almost totally useless for mathematical questions since it blocks most symbols.I am assuming that your question is about log base 3 of (x plus 1) plus log base 2 of (x-1).{log[(x + 1)^log2} + {log[(x - 1)^log3}/log(3^log2) where all the logs are to the same base - whichever you want. The denominator can also be written as log(3^log2)This can be simplified (?) to log{[(x + 1)^log2*(x - 1)^log3}/log(3^log2).As mentioned above, the expression can be to any base and so the expression becomesin base 2: log{[(x + 1)*(x - 1)^log3}/log(3) andin base 3: log{[(x + 1)^log2*(x - 1)}/log(2)
A log-log scale is a set of axes where each axis is logarithmic in scale.
to log in friendster.com
log(e)100 = log(10)100 / log(10)e = log(10)100 / log(10) 2.71828.... = 2/ 0.43429448... = 4.605170186..... (The answer). NB Note the change of log base to '10' However, on a calculator type in ;- 'ln' (NOT log). '100' '=' The answer shown os 4.605....
k=log4 91.8 4^k=91.8 -- b/c of log rules-- log 4^k=log 91.8 -- b/c of log rules-- k*log 4=log91.8 --> divide by log 4 k=log 91.8/log 4 k= 3.260
Not quite. The log(x/y) = log(x) - log(y) In words, this reads "The log of a quotient is the difference of the log of the numerator and the log of the denominator."
False When logs are taken, division becomes subtraction, so the log of a quotient is the log of the numerator minus the log of the denominator.
No. Insert the word "minus" in place of the word "plus", and you'll have a true statement.
True. For example: 4 X 104/2 X 108 = 2 X 10-4
It has no specific name. For example f(x) = sin(x)/log(x) where x not equal to 1
Using the properties of logarithms, specifically the quotient rule, we can simplify the expression log₆ 60 - log₆ 30 to log₆ (60/30). This simplifies to log₆ 2, since 60 divided by 30 equals 2. Therefore, log₆ 60 - log₆ 30 = log₆ 2.
4 divided by 84 in log div = 0.047619047619047616
The negative log of a number is the log of the number's reciprocal ('1' divided by the number).
The derivative of a log is as follows: 1 divided by xlnb Where x is the number beside the log Where b is the base of the log and ln is just the natural log.
0.55
VK= RT/ZF * log [I+]out/[I+]inAccording to this equation, the equilibrium potential for potassium (VK) is equal to the product of the gas constant (R) and the temperature in degrees Kelvin (T) divided by the product of the valence of potassium (Z) and the Faraday constant (F) multiplied by the natural log of the quotient derived from the external and internal concentrations of potassium. Thus,
To calculate the number of decibels that power-level-'A' is greater than power-level-'B',-- Divide 'A' by 'B'-- Take the 'log' of the quotient-- Multiply the 'log' by 10 .If the result is negative, then 'A' is that many decibels lower than 'B'.