answersLogoWhite

0

The browser which is used for posting questions is almost totally useless for mathematical questions since it blocks most symbols.

I am assuming that your question is about log base 3 of (x plus 1) plus log base 2 of (x-1).

{log[(x + 1)^log2} + {log[(x - 1)^log3}/log(3^log2) where all the logs are to the same base - whichever you want. The denominator can also be written as log(3^log2)


This can be simplified (?) to log{[(x + 1)^log2*(x - 1)^log3}/log(3^log2).


As mentioned above, the expression can be to any base and so the expression becomes

in base 2: log{[(x + 1)*(x - 1)^log3}/log(3) and

in base 3: log{[(x + 1)^log2*(x - 1)}/log(2)

User Avatar

Wiki User

8y ago

What else can I help you with?

Related Questions

How do you solve log x plus log 8 equals 1?

log(x)+log(8)=1 log(8x)=1 8x=e x=e/8 You're welcome. e is the irrational number 2.7....... Often log refers to base 10 and ln refers to base e, so the answer could be x=10/8


What is X3 plus X2 plus X plus 1 divided by X 1?

2x2+7/x1


X minus 1 plus 2 plus log x equals 3. find x?

Original Statement:x - 1 + 2 + log(x) = 3Simplify:x + 1 + log(x) = 3Subtract 1:x + log(x) = 2Lambert W-Function:x = (W(100*ln(10))/(ln(10)) = 1.7555794993... (rounded up).This considered log(x) to be base 10 log (x).


What is the answer to Log x plus 4 minus log6 equals 1?

log(x) + 4 - log(6) = 1 so log(x) + 4 + log(1/6) = 1 Take exponents to the base 10 and remember that 10log(x) = x: x * 104 * 1/6 = 10 x = 6/1000 or 0.006


What is log 1 to the base 1?

acording to me the value is 0 because the value of log 1 at any base is always 0.


Suppose aneq 0. Compute log 2a 2b in terms of a and b.?

Due to the rubbish browser that we are compelled to use, it is not possible to use any super or subscripts so here goes, with things spelled out in detail: log to base 2a of 2b = log to base a of 2b/log to base a of 2a = [(log to base a of 2) + (log to base a of b)] / [(log to base a of 2) + (log to base a of a)] = [(log to base a of 2) + (log to base a of b)] / [(log to base a of 2) + 1]


Log x plus 7 equals 1 plus Log x-1?

logx +7=1+log(x-1) 6=log(x-1)-logx 6=log[(x-1)/x] 10^6=(x-1)/x 1,000,000x=x-1 999,999x=-1 x=-1/999,999


Solve ln y equals xln e?

ln is the natural logarithm. That is it is defined as log base e. As we all know from school, log base 10 of 10 = 1 just as log base 3 of 3 = 1, so, likewise, log base e of e = 1 and 1.x = x. so we have ln y = x. Relace ln with log base e, and you should get y = ex


What is log to the base of 2 0.5?

- 1


What is log of 1 to base 10?

It is zero


What is log base 5of 125?

log(5)125 = log(5) 5^(3) = 3log(5) 5 = 3 (1) = 3 Remember for any log base if the coefficient is the same as the base then the answer is '1' Hence log(10)10 = 1 log(a) a = 1 et.seq., You can convert the log base '5' , to log base '10' for ease of the calculator. Log(5)125 = log(10)125/log(10)5 Hence log(5)125 = log(10) 5^(3) / log(10)5 => log(5)125 = 3log(10)5 / log(10)5 Cancel down by 'log(10)5'. Hence log(5)125 = 3 NB one of the factors of 'log' is log(a) a^(n) The index number of 'n' can be moved to be a coefficient of the 'log'. Hence log(a) a^(n) = n*log(a)a Hope that helps!!!!!


How do you swap two numbers without third variables?

If the variables are x1 & x2 the solution is : 1) x1=x1+x2; 2) x2=x1-x2; 3) x1=x1-x2; EX: x1=1 , x2=6; 1) x1= 1+6 = 7 2) x2= 7-6 =1 3 x1=7-1 =6 ============================================