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The log of a quotient is the log of a numerator divided by the log of the denominator?
For a quotient x/y , then its log is logx - log y . NOT log(x/y)
What is log log scale?
A log-log scale is a set of axes where each axis is logarithmic in scale.
How do you solve k equals log4 91.8?
k=log4 91.8 4^k=91.8 -- b/c of log rules-- log 4^k=log 91.8 -- b/c of log rules-- k*log 4=log91.8 --> divide by log 4 k=log 91.8/log 4 k= 3.260
What is log 100 base e?
log 100 base e = log 100 base 10 / log e base 10 log 100 base 10 = 10g 10^2 base 10 = 2 log 10 base 10 = 2 log e base 10 = 0.434294 (calculator) log 100 base e = 2/0.434294 = 4.605175
If log 12 equals 1.07918 then the anti-log equals?
log(10) 12 = 1.07918 Then the antilog is 12 = 10^(1.07918) You must specify the base to which to logarithm is functioning. Different log bases will give different answers.
What is the answer to log x6?
log(x6) = log(x) + log(6) = 0.7782*log(x) log(x6) = 6*log(x)
What is the name of the brains circulatory system?
tom dunsdons dad and mum log log log log log log log in my buttt
The log of a quotient is the log of the numerator divided by the log of the denominator?
Not quite. The log(x/y) = log(x) - log(y) In words, this reads "The log of a quotient is the difference of the log of the numerator and the log of the denominator."
The log of a quotient is the log of a numerator divided by the log of the denominator?
For a quotient x/y , then its log is logx - log y . NOT log(x/y)
If log a equals x and log b equals y what is log?
"Log" is not a normal variable, it stands for the logarithm function.log (a.b)=log a+log blog(a/b)=log a-log blog (a)^n= n log a
Is it log on to or log onto?
log on to
If 3 log x - 2 log y?
1
Log x - log 6 equals log 15?
log(x) - log(6) = log(15)Add log(6) to each side:log(x) = log(15) + log(6) = log(15 times 6)x = 15 times 6x = 90
Is log 5 equivalent to log 5-log 20?
No. log 20 is a positive number , so it you subtract it from log 5 you get less than log 5. However, log10 5 = 1 - log102 = 2- log1020 . or log 5 - log 20 = log 5 - log 4*5 = log 5 - (log 5 + log 4) = log 5 - log 5 - log 4 = - log 4 But we do not need to do all of these computations, because log 5 is different from log 5 - log 20 by the law of the equality that says two equals remain equal if and only if we subtract (in our case) the same thing from them.
How do you solve for a power in a math problem?
You have to use logarithms (logs).Here are a few handy tools:If [ C = D ], then [ log(C) = log(D) ]log(AB) = log(A) + log(B)log(A/B) = log(A) - log(B)log(Np) = p times log(N)
Log 2 plus log 4 equals log 2x?
log(2) + log(4) = log(2x)log(2 times 4) = log(2x)2 times 4 = 2 times 'x'x = 4
Log9x plus log x equals 4log10?
log(9x) + log(x) = 4log(10)log(9) + log(x) + log(x) = 4log(10)2log(x) = 4log(10) - log(9)log(x2) = log(104) - log(9)log(x2) = log(104/9)x2 = 104/9x = 102/3x = 33 and 1/3
