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Q: The number you are thinking of is between 12 and 32 when you divide it by 5 it leaves a remainder of 1 when i divide it by 4 it leaves a remainder of2?

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If you take the number 969 and subtract the 9 remainder you get 960. Because the number is even you can divide it by 2. 969/2 = 480R9. :)

Undefined: You cannot divide by zero

An aliquant is an integer which does not divide another into integral parts, and which therefore leaves a remainder.

26 is one possibility

26

430/9 leaves a remainder of 4+3+0 = 7 [only works for division by 9].430/9 leaves a remainder of 4+3+0 = 7 [only works for division by 9].430/9 leaves a remainder of 4+3+0 = 7 [only works for division by 9].430/9 leaves a remainder of 4+3+0 = 7 [only works for division by 9].

12 times. It then leaves a remainder of 5.

That depends what number you're dividing it by.

2521

213 when divided by 5, 6, or 7 has a remainder of 3.

5.2

3

try to divide it by the lowest prime number (2). If it leaves a remainder, try the next highest prime. In this case the lowest prime to divide 95 evenly is 5 and 5 x 19 is your answer as 19 is also a prime.

799

A number leaves reminder 6 when divided by 10. What is the remainder when the number is divided by 5? Justify your reasoning.

2

It is a factor of that number and leaves no remainder

This is almost equivalent to asking for the factors of 2000: If 2000 is divisible (for example) by 100, 2006 divided by 100 leaves a remainder of 6. However, you have to exclude numbers less than or equal to 6; for example, if you divide 2006 by 5, you get a remainder of 1, not 6. So, just find all the factors for 2000, then exclude those that are less than or equal to 6.This is almost equivalent to asking for the factors of 2000: If 2000 is divisible (for example) by 100, 2006 divided by 100 leaves a remainder of 6. However, you have to exclude numbers less than or equal to 6; for example, if you divide 2006 by 5, you get a remainder of 1, not 6. So, just find all the factors for 2000, then exclude those that are less than or equal to 6.This is almost equivalent to asking for the factors of 2000: If 2000 is divisible (for example) by 100, 2006 divided by 100 leaves a remainder of 6. However, you have to exclude numbers less than or equal to 6; for example, if you divide 2006 by 5, you get a remainder of 1, not 6. So, just find all the factors for 2000, then exclude those that are less than or equal to 6.This is almost equivalent to asking for the factors of 2000: If 2000 is divisible (for example) by 100, 2006 divided by 100 leaves a remainder of 6. However, you have to exclude numbers less than or equal to 6; for example, if you divide 2006 by 5, you get a remainder of 1, not 6. So, just find all the factors for 2000, then exclude those that are less than or equal to 6.

209

5

With exception of '2' all prime numbers are odd. Any odd number that ends in '5' is not a prime. Any number that ends in 0,2,4,6,8 are even and not primes. '9' is a composite number and not a prime. So you are left with 3 or 7 , which are primes. So taking a number , say '23' divide by '3' leaves a remainder of '2' so it is a prime. Similarly '23' divided by '7' leaves a remainder of '2' so 23 is a prime. If No remainder is left then the number is composite and not a prime. e.g. 4567 is it a prime ? Its odd so could be a prime Does it divide by '3' answer 1522 remainder '1' so it is a prime. Try '7' answer 652 remainder '3' it is a prime. Hence 4567 is a definite prime number.

119

8 can go into 38 - 4 times. This leaves a remainder of 6/8 or 3/4.

62 is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6.

LCM of 1 - 6 is 60 so 61 would leave a remainder of 1, but doesn't divide by 11. Try other multiples of 60 and add 1: 120 + 1 = 121 which is an exact multiple of 11, and there you have it!