How about 91
12.5
The number 68 goes into the number 100 1 time. It has a remainder of 32.
add the remainder. You cannot get there by multiplying as it'll leave you with a remainder
Excluding the 10 & 100, there are 89 numbers between the two figures. Out of those 89, only 2 numbers in every 10 are exactly divisible by 5. Therefore this leaves 89-17 which is 72.
I believe that 4604 works.
How about 91
77 77/3=25r2 77/5=15r2 77/7=11r0
Can 9 go into 9 and 100
12.5
1 can be divided into both numbers with no remainder
LCM(2, 3, 4, 5, 6, 10) = 60 so the number is 61.
The number 68 goes into the number 100 1 time. It has a remainder of 32.
add the remainder. You cannot get there by multiplying as it'll leave you with a remainder
Excluding the 10 & 100, there are 89 numbers between the two figures. Out of those 89, only 2 numbers in every 10 are exactly divisible by 5. Therefore this leaves 89-17 which is 72.
Yes, but not evenly (16 with remainder 4).
The integer is 157. 157/3 = 52 remainder 1 157/5 = 31 remainder 2 157/7 = 22 remainder 3