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The perimeter of a classroom is 84 feet whereas the width is 19 feet. work out the cost of its carpeting rs 13 per sq foot?
Wiki User
∙ 7y ago
The length of the classroom works out as 23 feet and the width is 19 feet
So: 23 times 19 = 437 square feet
Cost of carpeting: 437 times 13 = 5,681
Wiki User
∙ 7y ago
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What is the best algebraic representation of the rectangles perimeter?
It is: 2(x+y) = perimeter whereas x is the width and y is the length of the rectangle
How do you get the area if you have the width and the perimeter?
Perimeter = 2 lengths + 2 widths 1/2 perimeter = length + width Length = 1/2 perimeter - width Area = length x width That's (1/2 perimeter - width) x (width) .
How can you get the width when you have the perimeter and the length?
If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length
If the perimeter is 48 If the length is twic the width what is the length of rectangle?
perimeter = (2*length) + (2*width) length = 2*width so perimeter = (2*2*width) + 2*width = 6*width perimeter = 48 so you can figure out the width and length
What is the width length and perimeter where the area equals 40 cm?
First of all, the area cannot be 40 cm since an area is 2-dimensional whereas the measure given is 1-dimensional. Next, the shape is not defined and so the width, length and perimeter are indeterminate. Even if you assume that the shape is a rectangle, the width, length and perimeter are indeterminate. On the basis that the length is greater than the width, all that you can say is that the length will be greater than or equal to sqrt(40) = 6.324555 (to 6 dp), the width will be 40 divided by that length and the perimeter will be twice their sum. Some examples: Length = 8, width = 5, perimeter = 26 Length = 10, width = 4, perimeter = 28 Length = 40, width = 1, perimeter = 82 Length = 4000, width = 0.01, perimeter = 8000.02 Length = 4,000,000, width = 0.00001, perimeter = 8,000,000.00002 and so on, without limit.
What is one different way to to find the perimeter of a rectangle?
Length + length + width + width = perimeter. Length + width x 2 = perimeter
How do you find the length of a rectangle if the perimeter is 40 and the width is 2inches?
perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in
How do you find width when you have perimeter and length?
width = (perimeter-2*length)/2
How do you find the width of a rectangle if you know the perimeter and the length?
Perimeter = 2 * width + 2 * length, so rearranging --> width = (Perimeter / 2) - length
How can you calculate the length of a rectangle if the perimeter and the width are given?
Because the perimeter is lenght + length +width +width, you do perimeter - double the width, and then halve the remaining number. that should give you the length.
Estimate the width of a classroom window?
The estimate width of a classroom window would 2.8m
How do you find the length of a rectangle knowing the perimeter and the width?
You divide the perimeter by the width and you get the lenght
