The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
you need length and width length multiply width = area length + length + width + width = perimeter
Length + length + width + width = perimeter. Length + width x 2 = perimeter
perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in
You divide the perimeter by the width and you get the lenght
Length = (Perimeter - twice width) / 2
2*length + 2*width
by appying 2l+2w
length 18 width 7
Perimeter = 2*(L + W).