L = 2w + 1
2l + 2w = 26
2l + l - 1 = 26
l = 9
w = 4
If you increase the rectangle's length by a value, its perimeter increases by twice that value. If you increase the rectangle's width by a value, its perimeter increases by twice that value. (A rectangle is defined by its length and width, and opposite sides of a rectangle are the same length. The lines always meet at their endpoints at 90° angles.)
4cm by 13cm
The dimensions of the rectangle are 21 units by 9 units
2*L + 2*W = 30m L<2*W So, 2*L + L < 30m L < 10m
15m wide and 31m long
24m x 34m
The dimensions work out as length 15 units and width 8 units Check: 2*(15+8) = 46 units which is its perimeter
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
If you increase the rectangle's length by a value, its perimeter increases by twice that value. If you increase the rectangle's width by a value, its perimeter increases by twice that value. (A rectangle is defined by its length and width, and opposite sides of a rectangle are the same length. The lines always meet at their endpoints at 90° angles.)
4cm by 13cm
A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.
The dimensions of the rectangle are 21 units by 9 units
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
width=15 length=35
twice length + twice width = perimeter In this example, L= 3W 2(3W)+2(W)=64 8W=64 W=6 L =3W L=18 The dimensions of this rectangle are: 18 by 6
2*L + 2*W = 30m L<2*W So, 2*L + L < 30m L < 10m
15m wide and 31m long