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You forgot to copy the polynomial. However, the Fundamental Theorem of Algebra states that every polynomial has at least one root, if complex roots are allowed. If a polynomial has only real coefficients, and it it of odd degree, it will also have at least one real solution.

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Q: The polynomial given below has rootss?
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The polynomial given roots?

Do mean find the polynomial given its roots ? If so the answer is (x -r1)(x-r2)...(x-rn) where r1,r2,.. rn is the given list roots.


How do you rewrite an polynomial and standard form?

A polynomial, of degree n, in standard form is:anxn + an-1xn-1 + ... + a1x+ a0 = 0 where n is an integer and the ai are constants.The answer about how to rewrite a polynomial depends on the form that it is given in.A polynomial, of degree n, in standard form is:anxn + an-1xn-1 + ... + a1x+ a0 = 0 where n is an integer and the ai are constants.The answer about how to rewrite a polynomial depends on the form that it is given in.A polynomial, of degree n, in standard form is:anxn + an-1xn-1 + ... + a1x+ a0 = 0 where n is an integer and the ai are constants.The answer about how to rewrite a polynomial depends on the form that it is given in.A polynomial, of degree n, in standard form is:anxn + an-1xn-1 + ... + a1x+ a0 = 0 where n is an integer and the ai are constants.The answer about how to rewrite a polynomial depends on the form that it is given in.


When can you say a given expressions are polynomials?

you can say that it is polynomial if that have a exponent


How many terms are in the polynomial abc+ e-fg +h squared 2?

The terms in a polynomial are seperated by a + or - So in given polynomial there are 4 terms.... abc , e, fg and h²


What number comes next in this sequence 1 3 11 47 239 give answer with explanation?

821. The explantion is that they can be generated by the polynomial below: the only polynomial of degree 4. There are infinitely many other possibilities and given any "next number" it is possible to find a polynomial of degree 5 that will generate the 5 given numbers and the specified "next". Un = (53n4 - 486n3 + 1627n2 - 2250n + 1068)/12 for n = 1, 2, 3, ...

Related questions

What is the Greatest Common Factor for the given polynomial?

Since no polynomial was given, no answer will be given.


What value of b makes the polynomial below a perfect square?

None does, since there is no polynomial below.


What is the factorization of the polynomial below?

We can't answer that without knowing what the polynomial is.


What is the coefficient of the term of degree 7 in the polynomial below?

There is no polynomial below.(Although I'll bet there was one wherever you copied the question from.)


Which polynomial represents the sum below?

Answer this ques Which polynomial represents the sum below?(-x3 + 3x2 + 3) + (3x2 + x + 4)tion…


What is the difference in evaluating a polynomial and solving a polynomial?

Evaluating a polynomial is finding the value of the polynomial for a given value of the variable, usually denoted by x. Solving a polynomial equation is finding the value of the variable, x, for which the polynomial equation is true.


What is the factorization of the polynomial graphed below?

90


Factor the expression given below Write each factor as a polynomial in descending order x2 - 81?

-79


The polynomial given roots?

Do mean find the polynomial given its roots ? If so the answer is (x -r1)(x-r2)...(x-rn) where r1,r2,.. rn is the given list roots.


Which two values of x are roots of the polynomial below x2 plus 5x plus 11?

There are none because the discriminant of the given quadratic expression is less than zero.


How do you factor a polynomial with the equation of 6A2 - B 2?

The given polynomial does not have factors with rational coefficients.


How do you rewrite an polynomial and standard form?

A polynomial, of degree n, in standard form is:anxn + an-1xn-1 + ... + a1x+ a0 = 0 where n is an integer and the ai are constants.The answer about how to rewrite a polynomial depends on the form that it is given in.A polynomial, of degree n, in standard form is:anxn + an-1xn-1 + ... + a1x+ a0 = 0 where n is an integer and the ai are constants.The answer about how to rewrite a polynomial depends on the form that it is given in.A polynomial, of degree n, in standard form is:anxn + an-1xn-1 + ... + a1x+ a0 = 0 where n is an integer and the ai are constants.The answer about how to rewrite a polynomial depends on the form that it is given in.A polynomial, of degree n, in standard form is:anxn + an-1xn-1 + ... + a1x+ a0 = 0 where n is an integer and the ai are constants.The answer about how to rewrite a polynomial depends on the form that it is given in.