Do mean find the polynomial given its roots ? If so the answer is
(x -r1)(x-r2)...(x-rn) where r1,r2,.. rn is the given list roots.
The "roots" of a polynomial are the solutions of the equation polynomial = 0. That is, any value which you can replace for "x", to make the polynomial equal to zero.
You forgot to copy the polynomial. However, the Fundamental Theorem of Algebra states that every polynomial has at least one root, if complex roots are allowed. If a polynomial has only real coefficients, and it it of odd degree, it will also have at least one real solution.
A polynomial of degree ( n ) can have at most ( n ) unique roots. This is due to the Fundamental Theorem of Algebra, which states that a polynomial of degree ( n ) has exactly ( n ) roots in the complex number system, counting multiplicities. Therefore, if all the roots are distinct, the maximum number of unique roots is equal to the degree of the polynomial.
Rational roots
A fourth degree polynomial function can have up to four unique roots. However, the actual number of unique roots can be fewer, depending on the polynomial's coefficients and the nature of its roots. Roots can be real or complex, and some roots may be repeated (multiplicity). Thus, the number of unique roots can range from zero to four.
The given polynomial does not have factors with rational coefficients.
The "roots" of a polynomial are the solutions of the equation polynomial = 0. That is, any value which you can replace for "x", to make the polynomial equal to zero.
No integer roots. Quadratic formula gives 1.55 and -0.81 to the nearest hundredth.
You forgot to copy the polynomial. However, the Fundamental Theorem of Algebra states that every polynomial has at least one root, if complex roots are allowed. If a polynomial has only real coefficients, and it it of odd degree, it will also have at least one real solution.
Since no polynomial was given, no answer will be given.
A third degree polynomial could have one or three real roots.
Actually, the roots of a Hurwitz polynomial are in the left half of the complex plain, not on the imaginary axis. As for the reason, that is because the polynomial is DEFINED to be one that has that kind of roots.
In answering this question it is important that the roots are counted along with their multiplicity. Thus a double root is counted as two roots, and so on. The degree of a polynomial is exactly the same as the number of roots that it has in the complex field. If the polynomial has real coefficients, then a polynomial with an odd degree has an odd number of roots up to the degree, while a polynomial of even degree has an even number of roots up to the degree. The difference between the degree and the number of roots is the number of complex roots which come as complex conjugate pairs.
Rational roots
4, the same as the degree of the polynomial.
A third-degree equation has, at most, three roots. A fourth-degree polynomial has, at most, four roots. APEX 2021
There are none because the discriminant of the given quadratic expression is less than zero.