They are 39 and 52.
You had me until "product." The product of 4 digits can't be prime.
If the question is about the product of all odd digits, the answer is 945. Otherwise the question does not make sense.
Write down the numbers from 1000 to 9999.
To find the total number of digits used to print the numbers from 1 to 11,521, we can break it down by the number of digits in each range. From 1 to 9 (9 numbers) uses 9 digits, from 10 to 99 (90 numbers) uses 180 digits, from 100 to 999 (900 numbers) uses 2,700 digits, and from 1,000 to 11,521 (10,522 numbers) uses 42,088 digits. Adding these together, the total is 9 + 180 + 2,700 + 42,088 = 44,977 digits.
To find the total number of digits used in numbers from 51 to 5001, we can break it down into two parts. Numbers from 51 to 99: Each number in this range has 2 digits, so there are 49 numbers in total, resulting in 49 x 2 = 98 digits. Numbers from 100 to 5001: Each number in this range has 3, 4, or 5 digits. a. For numbers from 100 to 999, each number has 3 digits, so there are 900 numbers in total, resulting in 900 x 3 = 2700 digits. b. For numbers from 1000 to 5001, each number has 4 or 5 digits. There are 4002 numbers in total, and if we assume each has 4 digits, it would be 4002 x 4 = 16008 digits. Adding all these together, the total number of digits used in numbers from 51 to 5001 is 98 + 2700 + 16008 = 18706 digits.
You had me until "product." The product of 4 digits can't be prime.
If the question is about the product of all odd digits, the answer is 945. Otherwise the question does not make sense.
To find the fraction of 4-digit natural numbers with a product of their digits that is even, we first need to determine the total number of 4-digit natural numbers. There are 9000 such numbers (from 1000 to 9999). Next, we consider the conditions for the product of digits to be even. For a number to have an even product of digits, at least one of the digits must be even. There are 5 even digits (0, 2, 4, 6, 8) and 5 odd digits (1, 3, 5, 7, 9). Therefore, the fraction of 4-digit natural numbers with an even product of digits is 5/10 * 9/10 * 9/10 * 9/10 = 3645/9000 = 809/2000.
Ignore the decimal points and multiply the numbers to give the product: 308*29 = 8932Count the number of digits AFTER the decimal points in the two numbers. Two in the first and one in the second, making three in all.That is the number of digits after the decimal point that you want in the answer. So insert the decimal point that many digits from the end of the product.Thus 8932 becomes 8.932Done!
To find the last but one digit in the product of the first 75 even natural numbers, we need to consider the units digit of each number. Since we are multiplying even numbers, the product will end in 0. Therefore, the last but one digit (tens digit) will depend on the multiplication of the tens digits of the numbers. The tens digit will be determined by the pattern of the tens digits of the even numbers being multiplied.
47
Write down the numbers from 1000 to 9999.
To find the total number of digits used to print the numbers from 1 to 11,521, we can break it down by the number of digits in each range. From 1 to 9 (9 numbers) uses 9 digits, from 10 to 99 (90 numbers) uses 180 digits, from 100 to 999 (900 numbers) uses 2,700 digits, and from 1,000 to 11,521 (10,522 numbers) uses 42,088 digits. Adding these together, the total is 9 + 180 + 2,700 + 42,088 = 44,977 digits.
Consider the numbers A and B where A has m digits after the decimal point and B has n digits.Then find the multiple A'*B' where A' is A without its decimal point, and B' is B without its decimal point.In that answer insert the decimal point so that there are (m+n) digits after the decimal point.
if the product of two numbers is 810 if there hcf is 9 find Lcm
You need at least two numbers to find a product.
Two or more numbers are needed to find their product