-9y + 3x + 2 = 0
Put in point-slope form*:
0 = -9y + 3x + 2
9y = 3x + 2 Subtract (-9y) from both sides
y = (1/3)x + (2/9) Divide both sides by 9 and reduce fractions
It is now in point-slope form.
m = (1/3)
The slope is (1/3).
*Point-slope form is y = mx + b where m is the slope and b is the y-intercept.
Slope of given line = -3 Therefore, slope of perpendicular = 1/3
22
y = 0.25x + 2 The slope of the line is 0.25
The slope is 1 and the y intercept is 5
1
the slope is 2, the number in front of the 'x' term
Equation of given line: 3x + y = 15 or y = -3x + 15 Slope of given line = coefficient of x = -3 Slope of perperndicular = -1/(slope of given line) = -1 / (-3) = 1/3
the slope of the line is -4
It is 8 and the y intercept is 8
The slope of the line of 2x plus 2y equals 7 is (7/2x - 1).
Slope = 2
Slope: -9