The slope is 0.
-9/4 or -2.25
Put in this form to see. Y = mX + c9X + 3Y = 63Y = - 9X + 6Y = - 3X + 2=========The slope of the line you seek is - 3.
-9x+6y = 54 6y = 9x+54 y = 1.5x+9 slope = 1.5
9
9
9x+18y = 36 18y = -9x+36 y = -1/2x+2 which is now in slope intercept form the slope being -1/2
Write the given equation in the slope-intercept form, y = mx + b, where m is the slope of the line.9x - 3y = -81 (subtract 9x to both sides)-3y = -9x - 81 (divide by -3 to both sides)y = 3x + 27Thus, the slope of the line is 3.
9x+3y = 6 3y = -9x+6 y = -3x+2 which is now in slope-intercept form
5
No because they don't have the same slope (9x & 3x)
Centre of circle: (2, 1.25) Slope of line: 9/4 Equation of line: y-1.25 = 9/4(x-2) => 4y-5 = 9x-18 => 4y = 9x-13