To function form. - 7X - 4Y = 16 - 4Y = 7X + 16 Y = - 7/4X - 4 ------------------------ The slope is, - 7/4 --------
16
If you mean points of (1, 6) and (-5, -7) the slope works out as 13/6
Let (x1, y1) = (-1, -6) and (x2, y2) = (-2, 10). Then the slope,m = (y2 - y1)/(x2 - x1) = (10 - -6)/(-2 - -1) = 16/-1 = -1/16.So that the point-slope form of the equation of the given line is:(y - y1) = m(x - x1)(y - -6) = (-1/16)(x - -1)(y + 6) = (-1/16)(x + 1)
16 + 2x = 10 + 8x 2x - 8x = 10 - 16 -6x = -6 x = 1 Check: 16 + 2(1) = 10 + 8(1) 18 = 18
Slope of a line perpendicular to x-y=16
If: 3x+y = 16 Then: y = -3x+16 whereas -3 is the slope and 16 is the y intercept
The slope would be 3/4
If 8x + 4y = 16, then y = - 2x + 4 Thus the slope is -2 and the intercept is 4.
-14
-14
1.6x - 3.2y = 16 3.2y = 1.6x - 16 y = 0.5x - 5 So slope = coefficient of x = 0.5
The equation is -x -16 equals y. You find this by using the equation for a line mx plus b equals y, where 'm' is the slope and 'b' is the y-intercept. From the information given, you have two points which are 0.-16 ans -16,0. You can find 'm' the slope with the equation y2-y1/x2-x1, or -16-0/0- -16. This is -16/16 or -1 for m and the y-intercept is given as -16. So, substitute into the line equation these values to get the answer given.
dy/dx = 5/4
(0,2)
y = (a + 12)(x + 3) (line 1)y = 4ax (line 2)Since the equation of the second line is in a slope-intercept form, write the equation of the first line in the slope-intercept form, y = mx + b, where m is the slope of the line.y = (a + 12)(x + 3)y = a(x + 3) + 12(x + 3)y = ax + 3a + 12x + 36y = ax + 12x + 3a + 36y = (a + 12)x + 3a + 36, where the slope is a + 12y = 4ax, where slope is 4aSince the lines are parallel they must have the same slope. So that,a + 12 = 4a3a = 12a = 4Thus, when a = 4, the parallel lines have a slope of 16.
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