Slope of a line perpendicular to x-y=16
If: 3x+y = 16 Then: y = -3x+16 whereas -3 is the slope and 16 is the y intercept
The slope would be 3/4
If 8x + 4y = 16, then y = - 2x + 4 Thus the slope is -2 and the intercept is 4.
1.6x - 3.2y = 16 3.2y = 1.6x - 16 y = 0.5x - 5 So slope = coefficient of x = 0.5
3x + 5y = 16 5y = -3x + 16 y = -3/5 x + 16/5 By the slope-intercept form: y = mx + b where m = slope b = y-intercept Therefore, the slope is -3/5.
The equation is -x -16 equals y. You find this by using the equation for a line mx plus b equals y, where 'm' is the slope and 'b' is the y-intercept. From the information given, you have two points which are 0.-16 ans -16,0. You can find 'm' the slope with the equation y2-y1/x2-x1, or -16-0/0- -16. This is -16/16 or -1 for m and the y-intercept is given as -16. So, substitute into the line equation these values to get the answer given.
dy/dx = 5/4