Given the algebraic expression (3m - 2)2, use the square of a difference formula to determine the middle term of its product.
> square the 1st term >twice the product of the first and last term >square the last term
A perfect square trinomial results from squaring a binomial. Specifically, when a binomial of the form ( (a + b) ) or ( (a - b) ) is squared, it expands to ( a^2 + 2ab + b^2 ) or ( a^2 - 2ab + b^2 ), respectively. Both forms yield a trinomial where the first and last terms are perfect squares, and the middle term is twice the product of the binomial’s terms.
You really can't "prove" the formula. You use it. You first square the base 'b'. Then, you multiply that number by the height 'h'. Then, you divide the product of the base squared and height by 3. Boom! You get your answer. In my school, we get a formula sheet with all the formulas we will need to use. If you didn't understand the description above, here is the formula for a square pyramid:1/3b2 h.Hope this helped!
The first two terms in a binomial expansion that aren't 0
Genus
> square the 1st term >twice the product of the first and last term >square the last term
To calculate the cube of a binomial, you can multiply the binomial with itself first (to get the square), then multiply the square with the original binomial (to get the cube). Since cubing a binomial is quite common, you can also use the formula: (a+b)3 = a3 + 3a2b + 3ab2 + b3 ... replacing "a" and "b" by the parts of your binomial, and doing the calculations (raising to the third power, for example).
A perfect square trinomial results from squaring a binomial. Specifically, when a binomial of the form ( (a + b) ) or ( (a - b) ) is squared, it expands to ( a^2 + 2ab + b^2 ) or ( a^2 - 2ab + b^2 ), respectively. Both forms yield a trinomial where the first and last terms are perfect squares, and the middle term is twice the product of the binomial’s terms.
STEPS : FIRST TERM = the cube of the first term SECOND TERM=three times the product of the squareof first term and second term THIRD TERM=three times the product of first term and square of second term FOURTH TERM=THE CUBE OF THE LAST TERM ..
STEPS : FIRST TERM = the cube of the first term SECOND TERM=three times the product of the squareof first term and second term THIRD TERM=three times the product of first term and square of second term FOURTH TERM=THE CUBE OF THE LAST TERM ..
STEPS : FIRST TERM = the cube of the first term SECOND TERM=three times the product of the squareof first term and second term THIRD TERM=three times the product of first term and square of second term FOURTH TERM=THE CUBE OF THE LAST TERM ..
FOILMultiply First Outer Inner LastThen add the outer and inner.
The binomial usually has an x2 term and an x term, so we complete the square by adding a constant term. If the coefficient of x2 is not 1, we divide the binomial by that coefficient first (we can multiply the trinomial by it later). Then we divide the coefficient of x by 2 and square that. That is the constant that we need to add to get the perfect square trinomial. Then just multiply that trinomial by the original coefficient of x2.
A perfect square is a binomial squared, like (x+3)^2. You would calculate this by remembering: Square the first, twice the product, square the last. So x^2 (square the first), plus 6x (twice the product), plus 9 (square the last), so we get x^2+6x+9. We can factor this in reverse to see that this is a perfect square. With this simple trick, you can solve for perfect squares.
First i will explain the binomial expansion
You really can't "prove" the formula. You use it. You first square the base 'b'. Then, you multiply that number by the height 'h'. Then, you divide the product of the base squared and height by 3. Boom! You get your answer. In my school, we get a formula sheet with all the formulas we will need to use. If you didn't understand the description above, here is the formula for a square pyramid:1/3b2 h.Hope this helped!
You have to multiply each term in the first binomial, by each term in the second binomial, and add the results. The final result is usually a trinomial.