Sum of an arithmetic series:
Sum = (1st number + last number) x (the number of numbers) /2
Your first number is 2. Your last number is 2 x 100 = 200. The number of numbers in this series is 100 (says so in the question). So your sum equals:
(2 + 200) x 100 / 2 = 202 x 100 / 2 = 10100.
100
Sum of the first n even numbers starting with 0 (counting 0 as the first number, 2 would be the second number.... etc) is n x (n-1)
98. It's less than 100, and 9 + 8 = 17
101
No, the sum of a prime number and a composite number is not always even.
The sum of the 25 primes less than 100 is even (it is 1060).The first prime number is 2. Every other prime number is odd.So, of the 25 primes less than 100, one is even and 24 are odd.Any two odd numbers sum to an even number. Therefore, an even number of odd numbers has an even sum. So the sum of 24 odd numbers is even.Therefore, the sum of the 25 primes less than 100 is even.
100
No 5 odd numbers add up to 100. The sum of any two odd numbers is even. The sum of any two even numbers is even. So the sum of any 4 odd numbers must be even. Take that and add an odd number and the sum must be odd. Therefore, the sum of any 5 odd numbers must be odd. 100 is even. In conclusion: The sum of any odd number of odd numbers is odd.
102 + 32 = 100 + 9 =109 (not an even number)
No. Sum of odd + odd = even Sum of odd + even = odd Sum of even + even = even
Sum of the first n even numbers starting with 0 (counting 0 as the first number, 2 would be the second number.... etc) is n x (n-1)
98. It's less than 100, and 9 + 8 = 17
The sum of the first 100 positive even numbers is 10,100.
The sum of two odd numbers or two even numbers is an even number. The sum of an odd number and an even number is an odd number.
The sum of the first 100 positive even numbers is 10,100.
The sum of the first 100 even numbers is 10,100
The sum of an odd number and an even number is an odd number.