777/3 = 259. So the numbers are 258, 259 and 260.
//sum and product of 3 nos #include #include void main() { int a,b,c; printf("enter the 3 nos"); scanf("%d%d%d",&a,&b,&c); printf("sum of 3 nos",a+b+c); printf("product of 3 nos",a*b*c); getch(); }
Yes, the sum of any three consecutive counting numbers has a factor of 3.
It need not be. 2 and 3 are consecutive integers and their sum is 5, not 31.
3,5&7 3*5*7=105
The sum of 3 consecutive whole numbers is always equal to 3 times the middle number in that sequence.
The sum of any three consecutive even numbers must be divisible by 3. 32 is not, so there is no solution.
2 and 3.
You probably want to know "What are the 3 consecutive whole numbers whose sum is 72 ?" They are 23, 24, and 25.
Sorry. No sum of even numbers can be an odd number.
The sum is 3*(x-1) or 3x - 3
3 consecutive even integers whose sum is 396 are 130, 132 and 134.
There are four consecutive 3-digit numbers with a sum of 2,494: 622, 623, 624 and 625.