The average of five numbers whose sum is 200 will always be 40, no matter which numbers you choose. When finding an average, you add up the numbers (find the sum of the set), then divide by the number of terms. In this case, the sum will always be 200, and there will always be five terms. This will always result in an average of 40.
Ex/
1 + 2 + 3 + 4 + 190 = 200
200 / 5 = 40
40 + 40 + 80 + 24 + 16 = 200
200 / 5 = 40
50+ 50+50+50+50
Sum of 5 numbers with an average of 10 = 50
250
Average of five numbers is 82 so their sum is 82*5 = 410. Average of four of them is 80, so their sum is 80*4 = 320. So the fifth number is 410 - 320 = 90.
The sum of the four numbers would be equal to 5 x 4 = 20.
the sum of all numbers is 6*4=24 sum of two = 2*2=4 average of other four=24-4/4=5
Sum of 5 numbers with an average of 10 = 50
Their sum divided by 5.
If the average of 5 numbers is 86, then their sum is 430.If the average of 6 numbers is 84, then their sum is 504.The sum grew by (504 - 430) = 74, so that was the 6th number.
200*201/2=20100
If the sum of 5 = 28 then the average is 28 / 5 = 5.6 If the sum of the squares = 226 then the average is 226 / 5 = 45.2 From this information, and by a process of elimination, the numbers might be 1, 2, 6, 8 and 11.
The average of a group of numbers is equal to the sum of the numbers divided by the number of numbers. If you want to find the sum of the five numbers, just multiply 790.6 by 5 to get the sum, which is 3953
250
The average of a set of numbers is the sum of all the numbers, divided the amount of numbers in the sequence. For example, the average of 12, 14, 13, 15, and 20, would be the sum of the numbers, 74, divided by the amount of numbers in the sequence, 5. So the average is 74/5, which is 14.8.
Average of five numbers is 82 so their sum is 82*5 = 410. Average of four of them is 80, so their sum is 80*4 = 320. So the fifth number is 410 - 320 = 90.
The sum of the four numbers would be equal to 5 x 4 = 20.
1)start 2)input 5 numbers m,a,i,r,a 3)average=sum/5 4)printsum 5)stop
Assuming mean average: average = sum/number_of_items → 10 = sum/2 → sum = 10 x 2 = 20 So any two numbers with a sum of 10 have a mean average of 10, eg {5, 15}, {1, 19}, {0, 20}, {-5, 25}, etc. With the median average, for two numbers it is exactly the same as the mean average, so any pair of numbers that sum to 20 will do. With the mode average, only the case of the pair of numbers {10, 10} will suffice.