Trying a progression of 1 gives
x+(x+1)+(x+2)
3x+3=12
x=3
33+43+53 = 216 Nope.
Trying a progression of 2 gives
x+(x+2)+(x+4)
3x+6=12
x=2
23+43+63 = 287 Still nope.
Trying a progression of 3 gives
x+(x+3)+(x+6)=12
3x+9 = 12
3x=3
x=1
13+43+73= 1 + 64 + 343 = 408 ■
The sum of the first five prime numbers is 28. The sum of the cubes of the first three prime numbers is 160. The average of 28 and 160 is 94.
The difference of their cubes is 4.
The cube root of 5000 is approx 17.1 So the numbers 1 to 17 have cubes which are smaller than 5000 that is, there are 17 such numbers.
6
If they are standard cubes - with numbers from 1 to 6 - the probability is 0.
The sum of the first five prime numbers is 28. The sum of the cubes of the first three prime numbers is 160. The average of 28 and 160 is 94.
The cubes of all rational numbers will be rational. But the cubes of irrational numbers can be either.
The sum of the cubes of the first 100 whole numbers is 25,502,500.
All one digit numbers are palindromes.Cubic numbers are generally understood to be cubes of integers. So the numbers, 1 and 8 are both palindromic cubes.
Perfect cubes.
Cubes of squares or squares of cubes, like 1, 64 and 729.
The difference of their cubes is 4.
The cube root of 5000 is approx 17.1 So the numbers 1 to 17 have cubes which are smaller than 5000 that is, there are 17 such numbers.
You cannot. And not all number cubes have the numbers 1-6 on them. For example, a doubling cube for backgammon.You cannot. And not all number cubes have the numbers 1-6 on them. For example, a doubling cube for backgammon.You cannot. And not all number cubes have the numbers 1-6 on them. For example, a doubling cube for backgammon.You cannot. And not all number cubes have the numbers 1-6 on them. For example, a doubling cube for backgammon.
6
That means that you calculate the cubes of two numbers, and then either add or subtract them.
The numbers are 76 23 45