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Your sample space --> 3 + 2 + 4 = 9

For the first draw, P(Red) = 3/9


For the subsequent draw, your sample space is reduced by 1.


So P(Green|Red) is 4/8.


To get the total of this event happening, you times 3/9 with 4/8 which is 1/6.

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Q: There are 3 red 2 blue and 4 green marbles in a bagwhat is the probrobility of getting a red then a green without replacing the first one picked?
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