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Answered 2013-04-12 18:46:23
The probability of getting on the first draw a black ball is: P(B1) =
3/7.
The probability of getting a red ball given the event of drawing a black ball on the
first draw is: P(R2│B1) =
4/6.
The probability of drawing a black ball on the first draw and a red ball on the second draw is: P(B1UR2) =
P(B1)∙P(R
2│B1) =
(3/7)∙(4/6) =
0.2857... ~ 0.286 ~ ~ 28.6%
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