Best Answer

The probability of getting on the first draw a black ball is: P(B1) =

3/7.

The probability of getting a red ball given the event of drawing a black ball on the

first draw is: P(R2│B1) =

4/6.

The probability of drawing a black ball on the first draw and a red ball on the second draw is: P(B1UR2) =

P(B1)∙P(R

2│B1) =

(3/7)∙(4/6) =

0.2857... ~ 0.286 ~ ~ 28.6%

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Q: There are 7 balls in a box 3 black and 4 red a ball will be drawn and not replacecd then a second ball wil lbe drawn what is the chances it will be a black ball and then red ball?

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It is (7+4)/(7+5+4+4) = 11/20

if the balls are in the ratio of 7:10, then in every 7+10 = 17 of them 7 are white and 10 are black. With 136 marbles there are 136 ÷ 17 = 8 lots → there are 8 lots × 7 white/lot = 56 white.

If you put a ball in the sun, different colors would absorb or reflect the sun more or less. So that would heat up the air inside the ball and make it bigger or smaller. Black balls would be bigger and white ones smaller. ( NO PUN INTENDED)

17

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I am assuming that what you are talking about is the quest where you have to get BLACK balls of wool and give it to the farmer. You get black balls of wool by shearing the black sheep, then spinning the wool on the spinning wheel.

The probability of a black ball in bag 1 is 4/12 = 1/3. If you add 3 black balls to bag 2, it will contain 5 black balls out of 15: the probability of a black ball being 3/15 = 1/3.

Surprisingly, yes. In Black and White, if you trade with people from fifty different countries, you receive a second Master Ball.

11/18 x 10/17 = .359

3/12*3/11 = 9/132, or 6.818%.

If you draw enough balls, without replacement, the probability is 1.The answer depends onhow many balls are drawn, andwhether or not they are replaced.Unfortunately, your question gives no information on these matters.

You can get 2 Master Balls in both versions.

Chances are, probably not. Even if it does create a black hole, it would be extremely small and only last for a fraction of a second.

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