There is no information to justify a choice between the three options.
All the trigonometric functions are derived from the right angled triangle. If we consider the three sides (AB, BC, CA) of a triangle and the included angle. There is a possibility of getting six functions based on the ratios like AB/AC, BC/AC, AB/BC, BC/AB, AC/BC, AC/AB . So we will have six trigonometric functions
Commutativity.
Do you mean F = abc + abc + ac + bc + abc' ? *x+x = x F = abc + ac + bc + abc' *Rearranging F = abc + abc' + ab + bc *Factoring out ab F = ab(c+c') + ab + bc *x+x' = 1 F = ab + ab + bc *x+x = x F = bc
AB + AC + BC = 48 AB + (AB +9) + (AB + 9 + 3) = 48 Solve and AB = 9 So AB = 9, AC = 18 and BC = 21
Let ABCD be a rectangleAB = CD = 9 ftBC = DA(AB)x(BC) = 54 ftBC = 54/(AB) = 54/9 = 6 ftperimeter = (AB)+(BC)+(CD)+(DA) = 2(AB)+2(BC) = 2x9+2x6 = 30 ft
ABC
The real answer is Bc . Hate these @
All the trigonometric functions are derived from the right angled triangle. If we consider the three sides (AB, BC, CA) of a triangle and the included angle. There is a possibility of getting six functions based on the ratios like AB/AC, BC/AC, AB/BC, BC/AB, AC/BC, AC/AB . So we will have six trigonometric functions
yes because ab plus bc is ac
Commutativity.
yes it will definitely help you for BC next year.
ab+bc
Do you mean F = abc + abc + ac + bc + abc' ? *x+x = x F = abc + ac + bc + abc' *Rearranging F = abc + abc' + ab + bc *Factoring out ab F = ab(c+c') + ab + bc *x+x' = 1 F = ab + ab + bc *x+x = x F = bc
AB and BC are both radii of B. To prove that AB and AC are congruent: "AC and AB are both radii of B." Apex.
Toronto, ON Calgary, AB Halifax, NS Iqaluit, Nunavut Airdrie, AB Camrose, AB Lacombe, AB Red Deer, AB Burnaby, BC Colwood, BC Kelowna, BC Langley, BC Nanaimo, BC Brandon, MB Selkirk, MB Moncton, NB St. John's, NL Vaughan, ON Windsor, ON Beloeil, QC Bromont, QC Candiac, QC Chambly, QC Mercier, QC Mirabel, QC Prévost, QC Estevan, SK Yorkton, SK Probably missed a few.
Line AB is perpendicular to BC. you can say this like; Line AB is at a right angle to BC
AB + AC + BC = 48 AB + (AB +9) + (AB + 9 + 3) = 48 Solve and AB = 9 So AB = 9, AC = 18 and BC = 21