Area of a trangle = 1/2(base*height)
height or altitude = 2*(60/20) = 6 m
It can be any length at all. The length of one side imposes no limits at all on the altitude.
Use trigonometry knowing that the angle will be 60 degrees
The area of a triangle is one-half the product of the base and the height. Therefore, the base of this triangle must be 60/10 = 6 meters.
60 sq cm
Area of a triangle in square units = 0.5*base*height
The area of triangle is : 60.0
An equilateral triangle is baisicaly 2 30-60-90 tiangles put together. The height of the longer lg of a 30-60-90 triangle is always root 3 times the length of the shorter leg. Because the length of the shorter legs of the 2 30-60-90 triangles in the equilateral triangle is half the base, the altitude is 31/2/2*b where b is the base.
Since an equilateral triangle has three congruent sides (and 3 congruent angles, each of 60⁰), the length of each side is 32/3 cm. If we draw one of the altitudes of the triangle, then a right triangle is formed where the side of a triangle is the hypotenuse, and the altitude is opposite to a 60 degrees angle. So we have, sin 60⁰ = altitude/(32/3 cm) (multiply by 32/3 cm to both sides) (32/3 cm)sin 60⁰ = altitude 9.2 cm = altitude
It can be any length at all. The length of one side imposes no limits at all on the altitude.
Each side of the triangle is 45cm/3=15cm. The altitude divides the base into two equal segments of 7.5cm. This results in a right triangle with hypotenuse 15 cm and base 7.5cm. Pythagorus tells us a2+b2=c2 where a=altitude, b=base, c=hypotenuse. a2=c2-b2=152-7.52=225-56.25=168.75, a=12.99cm. Alternatively, the 3 angles of an equilateral triangle are all 60 degrees. The altitude divides one of these angles into two 30 degree angles. The cosine of 30 degrees is the opposite divided by the adjacent side. The adjacent side is the altitude. Thus a/c=cosine of 30 degrees, a=c X cos30 degrees = 15X0.866=12.99cm
Use trigonometry knowing that the angle will be 60 degrees
each angle is 60 degrees. If you know trigonometry sin 60 = Altitude/length of side (from Pythagoras) A = 9.526 inch Or, from Pythagoras theorem 5.5 squared + Altitude squared = 11 squared Altitude = 9.526
The area of a triangle is one-half the product of the base and the height. Therefore, the base of this triangle must be 60/10 = 6 meters.
60 sq cm
Area of a triangle in square units = 0.5*base*height
20. There are 3 sides to any triangle. For an equilateral triangle all 3 sides are the same length. Therefore for this triangle we can say that, where x equals the length of a side: 3x = 60 x = 60/3 x = 20
If one side of an equilateral triangle is 12 cm, then all sides are 12 cm and all angles are 60 degrees. An altitude dropped from any vertex in an equilateral triangle bisects the base, creating two identical Pythagorean triple triangles. Using our old friend the Pythagorean theorem we can calculate the altitude (= height) as follows"a2 + b2 = c62 + b2 = 12236 + b2 = 144b2 = 108b = 10.3923 cm.