It can be any length at all. The length of one side imposes no limits at all on the altitude.
The altitude forms a right angle triangle with half the side length and one side as the hypotenuse. Using Pythagoras: (½side)² + altitude² = side² → altitude² = side² - ¼side² → altitude² = ¾side² → altitude = (√3)/2 × side → altitude = (√3)/2 × 6 = 3√3 ≈ 5.2
Clarify what triangle side length you are looking for.
Multiply the altitude by [ 2 / sqrt(3) ] to get the length of the side.[ 2 / sqrt(3) ] is about 1.1547 (rounded)
It is: 11.5 cm because 0.5*11.5*16 = 92 square cm
The sides are 2*sqrt(3) units in length.
The altitude forms a right angle triangle with half the side length and one side as the hypotenuse. Using Pythagoras: (½side)² + altitude² = side² → altitude² = side² - ¼side² → altitude² = ¾side² → altitude = (√3)/2 × side → altitude = (√3)/2 × 6 = 3√3 ≈ 5.2
Clarify what triangle side length you are looking for.
No. The altitude is smaller.
Each side of the triangle is 16.16581 units in length.
Given an altitude of 12 units, an equilateral triangle has side lengths of 13.9 (13.85641) units.
Multiply the altitude by [ 2 / sqrt(3) ] to get the length of the side.[ 2 / sqrt(3) ] is about 1.1547 (rounded)
Height = sqrt(3)/2 * length of side So here, approx 4.3301 cm
With an altitude of 10 units, this triangle's sides each measure 11.55 (11.54701) units.
The length of each side is 9.2376 cm. (rounded)
The altitude of an equilateral triangle is (√3)/2*a. where 'a' is the side of the triangle. It can be just find by giving a perpendicular to the base of the triangle, the base of the triangle become a/2 and one side is a. so by applying Pythagoras theorem we will get the desired formula.
It is: 11.5 cm because 0.5*11.5*16 = 92 square cm
each angle is 60 degrees. If you know trigonometry sin 60 = Altitude/length of side (from Pythagoras) A = 9.526 inch Or, from Pythagoras theorem 5.5 squared + Altitude squared = 11 squared Altitude = 9.526