1/12 = 0.08333... ≈ 8.33%
p(1,3) = 1/6 (1/6) = 1/36
p(3,1) = 1/6 (1/6) = 1/36
p(2,2) = 1/6 (1/6) = 1/36
p((1,3)u(3,1)u(2,2)) = 1/36 +1/36 +1/36 = 3/36 = 1/12
It depends on the numbers on the 4 sided die. I don't believe that is a recognised standard.
If two six sided fair dice are rolled, the sum of the result of both dice that has the lowest probability to come up is 2 and 12. P(2) = 1/36. P(12) = 1/36.
The first dice can show any of the eight numbers. If the dice are to show different numbers the second dice has 7 different numbers out of a possible 8 to chose from. So the probability is 7/8 or 0.875 or 87.5% chance.
one in sixsame for any number
1/9
It depends on the numbers on the 4 sided die. I don't believe that is a recognised standard.
If two six sided fair dice are rolled, the sum of the result of both dice that has the lowest probability to come up is 2 and 12. P(2) = 1/36. P(12) = 1/36.
The first dice can show any of the eight numbers. If the dice are to show different numbers the second dice has 7 different numbers out of a possible 8 to chose from. So the probability is 7/8 or 0.875 or 87.5% chance.
3
The probability that the sum of the numbers rolled is either even or a multiple of 5 is 11/18.
It is 1/6.
one in sixsame for any number
It's1/12
Half the numbers are odd on each die. (1 - (0.5 * 0. 5)) = 0.75
1/9
You can't get 14 with two regular six-sided dice ! The highest you can get with one throw is 12.
The probability is 1, if the dice are rolled often enough.