FOR WIRE A ,
RA = rho L/A = rho L/pie* r square -equation 1
RB = rho 2L/pie(2r)square = rho 2L/4 pie*r square
=rho L/2 pie * r square -equation 2
RA/RB = rho L/pie * r square * 2 pie *r square/rho L
RA/RB = 2
RA = 2RB , RB = RA/2
1/Rp = 1/RA + 1/RB
=1/RA +1/RB
1/Rp = 3/RA
Rp/RA = 1/3
Hence the ratio is 1:3
The required resistance is 12/1.5 = 8Ω.Five 40Ω resistors in parallel have an effective resistance of 8Ω.
unit production is a combination of prodduction so connected that the relevant motion is fonished so etc.
When i will be a pro will help
You can only have a shape (like a polygon) if all sides are connected.
There is no way to answer the question. You would also need the equivalent resistance of the motor. 12 volt batteries are used in many cars. A car with a small engine will have a relatively small starter motor and may use less than 200 amps. A car with a larger engine may need a battery which is still 12 volt but provide 700 amps. V = I x R or I = V / R .... So if you know the resistance, R, then you divide to find the current, I.
Resistance is connected in parallel with voltmeter or say, voltmeter is connected in parallel with resistance.
The resulting resistance of the parallel combination will be the resistance of the original wire divided by n squared.
in voltmeter we have internal Resistance and connected in series , to current don't transfer in voltmeter , and we have internal resistance in ammeter and connected in parallel , to most current transfer through the ammeter.
In simple way resistor bank contains number of resistors in series or parallel combination. They are connected in parallel to decrease the resistance and increase current rating and power dissipation.And they are connected in series to increase resistance and power dissipation.
No. Load resistance is the value of the element actually doing the work of the circuit it is connected to. A speaker connected to an amplifier is the load.
There is no 'equivalent resistance' for three resistors connected in star.
It would be the sum of the two resistances, as they are connected in series.
When connected in series, the overall effective resistance of a bunch of individual resistors is the sum of the individual resistances. It's always more than the resistance of any individual. When connected in parallel, the reciprocal of the overall resistance of a bunch of individual resistors is the sum of the reciprocals of the individual resistances. It's always less than the resistance of any individual. When two resistors are connected in parallel, the overall effective resistance of the pair is (the product of the two individual resistances) divided by (the sum of the two individual resistances). It's always less than the smaller individual resistance.
Two resistors connected in parallel are 1/2 the sum of their resistance. The resistance of two resistors connected in series is the sum of their resistance. For example: The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in parallel is 100+200 divided by 2 = 150 ohms. The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in series 100+200= 300 ohms.
If additional resistance is connected in parallel with a circuit the supply voltage will decrease?
No change in supply voltage as additional resistance is connected in parallel circuit.
That's like having a series combination of 4 + 4 ohms, in parallel with another resistance of 4 ohms. Calculate the series resistance, then use the parallel formula to combine it with the third resistance.