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Using each digit only once list all possible 3 digit numbers that can be made with 2 or 4 or 7?
Wiki User
∙ 14y ago
There are only six: 247, 274, 427, 472, 724 and 742.
Wiki User
∙ 14y ago
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How many 3-digit numbers can be formed using 0123456789 when repetition is not allowed?
-123456786
What is a 6 digit number using only odd numbers 1 time each?
This is not possible, since there are only five single digit odd numbers, which are 1, 3, 5, 7 and 9.
How many 4 digit numbers can be formed by the digits 1 2 3 4 using each digit only once?
24 different numbers.
What is the least possible decimal using each digit 5-9 once?
It is .56789
What is the largest 6 digit number using only even numbers using each number only once?
998,000
How many 3-digit numbers can be formed using 0123456789 when repetition is not allowed?
-123456786
What is a 6 digit number using only odd numbers 1 time each?
This is not possible, since there are only five single digit odd numbers, which are 1, 3, 5, 7 and 9.
What are all the possible 5 digit codes using the numbers 0-9?
There are 10000 such codes. Each of the numbers 0-9 can be in the first position. With each such first digit, each of the numbers 0-9 can be in the second position. With each such pair of the first two digits, each of the numbers 0-9 can be in the third position. etc.
How many four digits numbers can be formed using 0123456789?
Assuming that the first digit of the 4 digit number cannot be 0, then there are 9 possible digits for the first of the four. Also assuming that each digit does not need to be unique, then the next three digits of the four can have 10 possible for each. That results in 9x10x10x10 = 9000 possible 4 digit numbers. If, however, you can not use the same number twice in completing the 4 digit number, and the first digit cannot be 0, then the result is 9x9x8x7 = 4536 possible 4 digit numbers. If the 4 digit number can start with 0, then there are 10,000 possible 4 digit numbers. If the 4 digit number can start with 0, and you cannot use any number twice, then the result is 10x9x8x7 = 5040 possilbe 4 digit numbers.
How many 3 digit counting numbers are not multiples of 5?
There are 720 of them. The three digit counting numbers are 100-999. All multiples of 5 have their last digit as 0 or 5. There are 9 possible numbers {1-9} for the first digit, There are 10 possible numbers {0-9} for each of the first digits, There are 8 possible numbers {1-4, 6-9} for each of the first two digits, Making 9 x 10 x 8 = 720 possible 3 digit counting numbers not multiples of 5.
How many 10 digit numbers can be formed using each digit once?
ten factorial = 10! = 3,628,800
How many three digit numbers containing 3 7 and 9 using each digit once?
six
How many 4 digit numbers can be formed by the digits 1 2 3 4 using each digit only once?
24 different numbers.
What are all the possible 4 digit codes using the numbers 0 to 9 without using the same digit twice in each code?
Any 4 from 10 in any order = 10 x 9 x 8 x 7 = 5040
What is the least possible decimal using each digit 5-9 once?
It is .56789
How many different numbers can you make with the digits 1 2 3 and 4 using each digit only once?
If you want 4-digit numbers, there are 24 of them.
What is the greatest 5-digit even number with no digit repeated?
Proceed from left to right, using the largest possible digit in each position.
