#include "stdio.h" #include "math.h" int main() { double result,degrees,radians; printf("Enter the no. of degrees : "); scanf("%lf",°rees); radians = degrees*(M_PI/180); result = sin(radians); printf("%lf\n",radians); printf("The sin() of %lf is %lf\n", degrees, result); return 0; }
sin2x + c
2.9
- cos(1 - X) + C
∫ cos(x) dx = -sin(x) + C
That depends on the value of x, and the value of c. The expression "x + c" can't be simplified, if that's what you mean.
#include double x, y;y = sin (x);
the value of sin(x) lies between -1 to +1. the approx value of sin(x)/x = 1 when x tends to 0 & sin(x)/x = 0 when x tends to infinity.
Sin(x) has a maximum value of +1 and a minimum value of -1.
The integral of cot (x) dx is ln (absolute value (sin (x))) + C. Without using the absolute value, you can use the square root of the square, i.e. ln (square root (sin2x)) + C
The answer will depend on where, in the sine function, the x-value appears: For example, its roles in f(x) = sin(x), or f(x, theta) = x*sin(theta) or f(x, theta) = sin(x*theta) f(theta) = sin(theta + x) are quite different.
sin2x + c
Y=sin X is a function because for each value of X, there is exactly one Y value.
x = sin-1 (4/15) ( sin -1 is [SHIFT] [sin] on a calculator ) = 15.5
2.9
2 sin(x) - 3 = 0 2 sin(x) = 3 sin(x) = 1.5 No solution. The maximum value of the sine function is 1.0 .
- cos(1 - X) + C
∫ cos(x) dx = -sin(x) + C