sin2x + c
2.9
- cos(1 - X) + C
∫ cos(x) dx = -sin(x) + C
There is more than one equivalent definition. One way to think of this is this: Imagine a right triangle, with an angle "x". The sides of the triangles are as follow: side "a" is opposite to the angle "x", side "b" is adjacent to the angle, and side "c" is the hypothenuse (the longest side, opposite the right angle). In this case: * sin(x) = a/c * cos(x) = b/c * tan(x) = a/b = sin(x) / cos(x) * cot(x) = b/a = cos(x) / sin(x) * csc(x) = c/a = 1 / sin(x) * sec(x) = c/b = 1 / cos(x) These ratios of sides will depend on the angle "x", but for any angle "x", the ratio will always be the same. For example, for an angle of 30°, the ratio a/c (sine of x) will always be 1/2.
#include double x, y;y = sin (x);
the value of sin(x) lies between -1 to +1. the approx value of sin(x)/x = 1 when x tends to 0 & sin(x)/x = 0 when x tends to infinity.
Sin(x) has a maximum value of +1 and a minimum value of -1.
The integral of cot (x) dx is ln (absolute value (sin (x))) + C. Without using the absolute value, you can use the square root of the square, i.e. ln (square root (sin2x)) + C
The answer will depend on where, in the sine function, the x-value appears: For example, its roles in f(x) = sin(x), or f(x, theta) = x*sin(theta) or f(x, theta) = sin(x*theta) f(theta) = sin(theta + x) are quite different.
sin2x + c
Y=sin X is a function because for each value of X, there is exactly one Y value.
x = sin-1 (4/15) ( sin -1 is [SHIFT] [sin] on a calculator ) = 15.5
2.9
2 sin(x) - 3 = 0 2 sin(x) = 3 sin(x) = 1.5 No solution. The maximum value of the sine function is 1.0 .
- cos(1 - X) + C
∫ cos(x) dx = -sin(x) + C